Star’s R.A. 6 54 57 ·1 ------------ _t_ 2 32 43 ·3 = 38° 10′ 49″·5 E. of meridian. ------------ - φ = 24° 20′ 50″ log sin 1·6151769 - δ = 28° 50′ 52″·7 log sin 1·6834857 --------- - 1·2986626 Nat. (1) 0·1989128 --------- - φ = 24° 20′ 50″ log cos 1·9595488 - - δ = 28° 50′ 52″·7 log cos 1·9424561 log cos δ 1·9424 - - _t_ = 38° 10′ 49″·5 log cos 1·8954602 log sin _t_ 1·7911 --------- ------ - - 1·7974651 1·7335 --------- - Nat. (2) 0·6272853 log cos _h_ 1·9560 ------ - Nat. (1) 0·1989128 log sin _A_ 1·7775 --------- - 0·4283725 log cos φ 1·9595 - ------ log sin _h_ 1·6318215 1·7370 Nat. = 0·546 _h_ = 25° 21′ 51″·5 - log cos _A_ 1·9034 Nat. = 0·801 Whence the equation for ε _Canis majoris_ is 51·5 − 0·801 _d_φ + 0·546 _dT_ − _h_0 = 0 (3) Collecting the equations of the three stars, we have 35·8 + 1·000 _d_φ − 0·011 _dT_ − _h_0 = 0 (1) 51·1 − 0·896 _d_φ + 0·404 _dT_ − _h_0 = 0 (2) 51·5 − 0·801 _d_φ + 0·546 _dT_ − _h_0 = 0 (3) By solving these equations for _d_φ, we find _d_φ = + 6″·5 whence the latitude is found to be 24° 20′ 56″·5