Algorithms; Arithmetic -- Early works to 1900; Mathematics -- History
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o | o
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Then shall I begynne to subtracte the greatest nombres fyrste (contrary
to the vse of the penne) y^t is the thousandes in this exa{m}ple:
therfore I fynd amongest the thousandes 2, for which I withdrawe so many
fro{m} the seconde summe (where are 8) and so remayneth there 6, as this
exa{m}ple showeth.
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| o
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o | o
----o-o-o----+--o-o---------
o |
----o-o-o-o--+--o-o-o-o-----
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Then do I lyke wayes with the hundredes, of whiche in the fyrste summe
[*116b] I fynde 8, and is the seconde summe but 7, out of whiche I can
not take 8, therfore thus muste I do: I muste loke how moche my summe
dyffereth from 10, whiche I fynde here to be 2, then must I bate for my
su{m}me of 800, one thousande, and set downe the excesse of hundredes,
that is to saye 2, for so moche 100[0] is more then I shuld take vp.
Therfore fro{m} the fyrste su{m}me I take that 800, and from the second
su{m}me where are 6000, I take vp one thousande, and leue 5000; but then
set I downe the 200 unto the 700 y^t are there all redye, and make them
900 thus.
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| o
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o |
----o-o-o-o--+--o-o-o-o-----
| o
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Then come I to the articles of te{n}nes where in the fyrste su{m}me I
fynde 90, [*117a] and in the seconde su{m}me but only 40: Now
consyderyng that 90 can not be bated from 40, I loke how moche y^t 90
doth dyffer from the next summe aboue it, that is 100 (or elles whiche
is all to one effecte, I loke how moch 9 doth dyffer fro{m} 10) {and} I
fynd it to be 1, then in the stede of that 90, I do take from the second
summe 100: but consyderynge that it is 10 to moche, I set downe 1 in y^e
nexte lyne beneth for it, as you se here.
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| o
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Sauynge that here I haue set one counter in y^e space in stede of 5 in
y^e nexte lyne. And thus haue I subtracted all saue two, which I must
bate from the 6 in the second summe, and there wyll remayne 4, thus.
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| o
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----+--o-o-o-o-----
Public-domain text, read in full here on John Shaqi.
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