A text-book of assaying : $b for the use of those connected with mines.Beringer, C. (Cornelius)
Science
A text-book of assaying : $b for the use of those connected with mines.
Beringer, C. (Cornelius)
Assaying
------------+----------+----------+-----------+-----------+------------
When, as in this table, the fraction of an ounce is expressed by two
places of decimals, it may be reduced to pennyweights (dwts.) by
dividing by 5. For example, 0.40 of an ounce is 8 dwts. The fraction of
a dwt. similarly expressed may be converted into grains with sufficient
exactness by dividing by 4. Thus, 1.63 ozs. equal 1 oz. 12.60 dwts., or
1 oz. 12 dwts. 15 grains. In England it is usual to report in ounces and
decimals of an ounce.
The way to use the table is best shown by an example. Suppose a button
of silver weighing 0.0435 gram was obtained from 20 grams of ore. Look
down the 20-gram column of the table, and select the values
corresponding to each figure of the weight, thus:--
0.04 = 65.33 ozs. to the ton
0.003 = 4.90 "
0.0005 = 0.82 "
------ -----
0.0435 = 71.05 "
Add these together. The produce is 71.05 ozs., or 71 ozs. 1 dwt. to the
ton.
Or, suppose an ore is known to contain 1.24 per cent. of silver. Look
down the 100-gram column, select the values, and add them together as
before.
1.0 = 326.67 ozs. per ton
0.2 = 65.33 "
0.04 = 13.07 "
---- ------
1.24 = 405.07 "
This gives 405 ozs. 1 dwt. 10 grains to the ton.
The calculation becomes more complicated when, as is frequently the
case, the ore contains metallic particles. These show themselves by
refusing to pass through the sieve when the ore is powdered. When they
are present, a large portion, or if feasible the whole, of the sample is
powdered and sifted. The weights of the sifted portion and of the
"metallics," or prills, are taken; the sum of these weights gives that
of the whole of the sample taken. It is very important that nothing be
lost during the operation of powdering.
Each portion has to be assayed separately. It is usual to assay a
portion of the sifted sample, say, 20 or 50 grams, and to add to the
produce of this its share of the "metallics." This way of calculating,
which is more convenient than correct, is illustrated by the following
example:--
Weight of whole sample 400 grams
Made up of sifted portions 399 "
" "Metallics" 1 "
---
400 "
Twenty grams of the sifted portion, when assayed, gave 0.1050 gram of
silver. The whole of the "metallics" scorified and cupelled gave 0.842
gram of silver. Since the 20 grams assayed was 1-20th of the whole,
1-20th part of the 0.842 gram of silver (from the metallics) must be
added to its produce. We thus get 0.1471 gram (0.1050 + 0.0421).
Referring to the 20 gram column, we get--
0.1 = 163.33
0.04 = 65.33
0.007 = 11.43
0.0001 = 0.16
------ ------
0.1471 = 240.25 ounces per ton.
Public-domain text, read in full here on John Shaqi.
Reviews
Reviews
No reviews yet
Be the first to share your thoughts on this work.
Elsewhere in the archive
Join the Discussion
Join the discussion
Sign in to leave a comment or review.
Sign InorCreate an account