A Text-Book of AstronomyComstock, George C. (George Cary)
Science
A Text-Book of Astronomy
Comstock, George C. (George Cary)
Astronomy
Numerically, Newton's correction to Kepler's Third Law does not amount
to much in the motion of the planets. Jupiter, which shows the greatest
effect, makes the circuit of his orbit in 4,333 days instead of 4,335,
which it would require if Kepler's law were strictly true. But in
another respect the change is of the utmost importance, since it enables
us to extend Kepler's law, which relates solely to the sun and its
planets, to other attracting bodies, such as the earth, moon, and stars.
Thus for the moon's motion around the earth we write--
(240,000^{3})/(27.32^{2}) = k (1 + 1/81),
from which we may find that, with the units here employed, the earth's
mass as the unit of mass, the mean solar day as the unit of time, and
the mile as the unit of distance--
k = 1830 × 10^{10}.
If we introduce this value of _k_ into the corresponding equation, which
represents the motion of the earth around the sun, we shall have--
a^{3}/(365.25)^{2} = 1830 × 10^{10} (333,000 + 1),
where the large number in the parenthesis represents the number of times
the mass of the sun is greater than the mass of the earth. We shall find
by solving this equation that _a_, the mean distance of the sun from the
earth, is very approximately 93,000,000 miles.
113. ANOTHER METHOD OF DETERMINING THE SUN'S DISTANCE.--This will be
best appreciated by a reference to Fig. 17. It appears here that the
earth makes its nearest approach to the orbit of Mars in the month of
August, and if in any August Mars happens to be in opposition, its
distance from the earth will be very much less than the distance of the
sun from the earth, and may be measured by methods not unlike those
which served for the moon. If now the orbits of Mars and the earth were
circles having their centers at the sun this distance between them,
which we may represent by _D_, would be the difference of the radii of
these orbits--
D = a´´ - a´,
where the accents ´´, ´ represent Mars and the earth respectively.
Kepler's Third Law furnishes the relation--
(a´´)^{3}/(T´´)^{2} = (a´)^{3}/(T´)^{2};
and since the periodic times of the earth and Mars, _T´_, _T´´_, are
known to a high degree of accuracy, these two equations are sufficient
to determine the two unknown quantities, _a´_, _a´´_--i. e., the
distance of the sun from Mars as well as from the earth. The first of
these equations is, of course, not strictly true, on account of the
elliptical shape of the orbits, but this can be allowed for easily
enough.
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