By these formularies, if the height through which a body falls freely
in one second be known, the height through which it will fall in any
proposed time may be computed. For since the height is proportional
to the square of the time, the height through which it will fall in
_two_ seconds will be _four_ times that which it falls through in
_one_ second. In _three_ seconds it will fall through _nine_ times
that space; in _four_ seconds, _sixteen_ times; in _five_ seconds,
_twenty-five_ times, and so on. The following, therefore, is a general
rule to find the height through which a body will fall in any given
time: “Reduce the given time to seconds, take the square of the number
of seconds in it, and multiply the height through which a body falls in
one second by that number; the result will be the height sought.”
The following table exhibits the heights and corresponding times as far
as 10 seconds:
+-------+---+---+---+----+----+----+----+----+----+-----+
|Time | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
+-------+---+---+---+----+----+----+----+----+----+-----+
|Height | 1 | 4 | 9 | 16 | 25 | 36 | 49 | 64 | 81 | 100 |
+-------+---+---+---+----+----+----+----+----+----+-----+
Each unit in the numbers of the first row expresses a second of time,
and each unit in those of the second row expresses the height through
which a body falls freely in a second.
(122.) If a body fall continually for several successive seconds,
the spaces which it falls through in each succeeding second have a
remarkable relation among each other, which may be easily deduced from
the preceding table. Taking the space moved through in the first second
still as our unit, four times that space will be moved through in the
first two seconds. Subtract from this 1, the space moved through in the
first second, and the remainder 3 is the space through which the body
falls in the _second_ second. In like manner if 4, the height fallen
through in the first two seconds, be subtracted from 9, the height
fallen through in the first three seconds, the remainder 5 will be the
space fallen through in the third second. To find the space fallen
through in the fourth second, subtract 9, the space fallen through in
the first three seconds, from 16, the space fallen through in the first
four seconds, and the result is 7, and so on. It thus appears that if
the space fallen through in the first second be called 1, the spaces
described in the second, third, fourth, fifth, &c. seconds, will be
expressed by the odd numbers respectively, 3, 5, 7, 9, &c. This places
in a striking point of view the accelerated motion of a falling body,
the spaces moved through in each succeeding second being continually
increased.
Public-domain text, read in full here on John Shaqi.
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