Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.Baldwin, Thomas
History
Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.
Baldwin, Thomas
Aeronautics -- Early works to 1900; Balloons -- Early works to 1800
_End of the last Stage._
CHAPTER LXXVIII.
PRACTICE OF THE FOURTH EXAMPLE,[134] FOR MEASURING SMALL HEIGHTS.
[Sidenote: By this Example, _small_ Heights are easily measured.]
Section 419. Attached Therm. _below_, 71°.0
Attached Therm. _above_, 70 .5
—————
Subtract, and there remains .5 Tenths of a Degree of
Heat to be added to the _colder_ Barometer (which in the present Case
is the _upper_, but might possibly have been otherwise) by the 1st
Table.
_First_, _with_ 0°.5 _on_ 29 Inches. To obtain which, begin
_with_ 1°.0 _on_ 29 Inches = .002:
_with_ 0°.1 above 1°, _on_ 29 = .0002: then
_with_ 0°.5 above 1°, _on_ 29 = .001.
Prepare it for Addition to the _colder_ Barometer.
colder Barometer 29.985
Expansion _with_ .5 above 1°, _on_ 29 .001
——————
29.986
_Secondly_, _with_ .5 Tenths above 1°, _on_ .985 Tenths above 29
Inches. To obtain which, (having already found the Height from
Expansion _with_ .5 above 1°, _on_ 29 Inches, to be .001;) since the
Expansion on .985 Tenths above 29 Inches, is somewhere above 29, yet
below 30 Inches; find the Expansion _with_ .5 above 1°, _on_ 30
Inches, thus:
first, _with_ 1°, _on_ 30 = .003
2d. _with_ 0°.1 above 1°, _on_ 30 = .0003
3d. _with_ 0°.5 above 1°, _on_ 30 = .0015
Subtract the Expansion _with_ .5 Tenths above 1°, _on_ 29 Inches, from
the Expansion _with_ .5 Tenths above 1°, _on_ 30 Inches:
viz. _on_ 30 = .0015
_on_ 29 = .001
—————
The Answer is .0005, the Height from Expansion, _with_ .5 Tenths
above 1°, _on_ 1 Inch above 29, i.e. on the 30th Inch: Then, if 1 Inch
above 29 gives .0005; .1 gives .00005:
and 985
———————
multiplied 00025
as whole 00040
Numbers, 00045
————————
give .0004|925
add the former Number 29.986
and, for the three remaining Decimals,
_may_ be substituted 1 Decimal
in the fourth Place 1
———————
colder Barometer of equal Heat } 29.9865
with the _warmer_ }
420. _When the Quicksilver in each Barometer indicates the same Number
of Inches_, differing _but_ one _or_ two Tenths _at the most; (which
will frequently be the Case, in levelling flat Countries, or measuring
small Heights;—instead of the usual Method, (to find the Height of each
Barometer_ separately, _with the Standard-Heat, by the_ 2d Column _of
the 2d Table, as in Section 411;)—it will be more convenient,_
Public-domain text, read in full here on John Shaqi.
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