Taking up the number, 31,741, which we have chosen for our first example,
let us deduct from it the highest multiple of 13 which it contains. This
will be found by dividing the number by 13, and multiplying the
_whole-number part_ of the resulting quotient by 13: 31,741 ÷ 13 =
2,441-8/13. Multiplying 2,441 by 13, we have 31,733, which is the highest
multiple of 13 that 31,741 contains; consequently it may be deducted from
31,741 without affecting the value of the resulting day coefficient: 31,741
- 31,733 = 8. In the example under consideration, therefore, 8 is the
number which, if counted from the day coefficient of the starting point,
will give the day coefficient of the resulting date. In other words, after
dividing by 13 the only part of the resulting quotient which is used in
determining the new day coefficient is the _numerator_ of the fractional
part.[100] Hence the following rule for determining the first unknown on
page 138 (the day coefficient):
_Rule 1._ To find the new day coefficient divide the given number by 13,
and count forward the numerator of the fractional part of the resulting
quotient from the starting point if the count is forward, and backward if
the count is backward, deducting 13 in either case from the resulting
number if it should exceed 13.
Applying this rule to 31,741, we have seen above that its division by 13
gives as the fractional part of the quotient 8/13. Assuming that the count
is forward from the starting point, 4 Ahau 8 Cumhu, if 8 (the numerator of
the fractional part of the quotient) be counted forward from 4, the day
coefficient of the starting point (4 Ahau 8 Cumhu), the day coefficient of
the resulting date will be 12 (4 + 8). Since this number is below 13, the
last sentence of the above rule has no application in this case. In
counting forward 31,741 from the date 4 Ahau 8 Cumhu, therefore, the day
coefficient of the resulting date will be 12; thus we have determined our
first unknown. Let us next find the second unknown, the day sign to which
this 12 is prefixed.
It was explained on page 37 that the twenty day signs given in Table I
succeed one another in endless rotation, the first following immediately
the twentieth no matter which one of the twenty was chosen as the first.
Consequently, it is clear that the highest multiple of 20 which the given
number contains may be deducted from it without affecting in any way the
name of the day sign of the date which the number will reach when counted
from the starting point. This is true because, no matter what the day sign
of the starting point may be, any multiple of 20 will always bring the
count back to the same day sign. {140}
Public-domain text, read in full here on John Shaqi.
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