| 64|1,214,720| 8. 8. 14. 4. 0| +--------+---------+-----------------+ | 65|1,233,700| 8. 11. 6. 17. 0| +--------+---------+-----------------+ | 66|1,252,680| 8. 13. 19. 12. 0| +--------+---------+-----------------+ | 67|1,271,660| 8. 16. 12. 7. 0| +--------+---------+-----------------+ | 68|1,290,640| 8. 19. 5. 2. 0| +--------+---------+-----------------+ | 69|1,309,620| 9. 1. 17. 15. 0| +--------+---------+-----------------+ | 70|1,328,600| 9. 4. 10. 10. 0| +--------+---------+-----------------+ | 71|1,347,580| 9. 7. 3. 5. 0| +--------+---------+-----------------+ | 72|1,366,560| 9. 9. 16. 0. 0| +--------+---------+-----------------+ | 73|1,385,540| 9. 12. 8. 13. 0| +--------+---------+-----------------+ | 74|1,404,520| 9. 15. 1. 8. 0| +--------+---------+-----------------+ | 75|1,423,500| 9. 17. 14. 3. 0| +--------+---------+-----------------+ | 76|1,442,480|10. 0. 6. 16. 0| +--------+---------+-----------------+ | 77|1,461,460|10. 2. 19. 11. 0| +--------+---------+-----------------+ | 78|1,480,440|10. 5. 12. 6. 0| +--------+---------+-----------------+ | 79|1,499,420|10. 8. 5. 1. 0| +--------+---------+-----------------+ | 80|1,518,400|10. 10. 17. 14. 0| +--------+---------+-----------------+ {145} Let us count forward the number 5,799 from the starting point 2 Kan 7 Tzec. It is apparent at the outset that, since this number is less than 18,980, or 1 Calendar Round, the preliminary rule given on page 143 does not apply in this case. Therefore we may proceed with the first rule given on page 139, by means of which the new day coefficient may be determined. Dividing the given number by 13 we have: 5,799 ÷ 13 = 446-1/13. Counting forward the numerator of the fractional part of the resulting quotient (1) from the day coefficient of the starting point (2), we reach 3 as the day coefficient of the terminal date. The second rule given on page 140 tells how to find the day sign of the terminal date. Dividing the given number by 20, we have: 5,799 ÷ 20 = 289-19/20. Counting forward the numerator of the fractional part of the resulting quotient (19) from the day sign of the starting point, Kan, in the sequence of the twenty-day signs given in Table I, the day sign Akbal will be reached, which will be the day sign of the terminal date. Therefore the day of the terminal date will be 3 Akbal.