B1 = 9 × 144,000 = 1,296,000 A2 = 2 × 7,200 = 14,400 B2 = 13 × 360 = 4,680 A3 = 0 × 20 = 0 B3 = 0 × 1 = 0 --------- 1,315,080 Deducting all the Calendar Rounds possible from this number, 69 (see Table XVI), and applying rules 1, 2, and 3 (pp. 139, 140, and 141, respectively) to the remainder, the terminal date reached will be 4 Ahau 13 Kayab. It remains to find this date in the text. The glyph in A4, the proper position for the day glyph, is somewhat effaced, though the profile of the human head may yet be traced, thus enabling us to identify this form as the day sign Ahau. Compare figure 16, _h', i'_. The coefficient of A4 is very clearly 4 dots, that is, 4, and consequently this glyph agrees with the day as determined by calculation, 4 Ahau. Passing over B4, A5, B5, and A6, we reach in B6 the closing glyph of the Supplementary Series, here recorded with a coefficient of 9. Compare B6 with figure 65. The month glyph follows in A7 with the coefficient 13. Comparing this latter glyph with the month signs in figure 19, it is evident that the month Kayab (fig. 19, _d'-f'_) is recorded in A7, which reads, therefore, 13 Kayab. Hence the whole text records the Initial Series 9.2.13.0.0 4 Ahau 13 Kayab. [Illustration: GLYPHS REPRESENTING INITIAL SERIES, SHOWING USE OF BAR AND DOT NUMERALS AND HEAD-VARIANT PERIOD GLYPHS--STELA 3, TIKAL] [Illustration: GLYPHS REPRESENTING INITIAL SERIES, SHOWING USE OF BAR AND DOT NUMERALS AND HEAD-VARIANT PERIOD GLYPHS--STELA A (EAST SIDE), QUIRIGUA] {179} This Initial Series is extremely important, because it records the earliest contemporaneous[148] date yet found on a monument[149] in the Maya territory. In plate 11 is figured the Initial Series from the east side of Stela A at Quirigua.[150] The introducing glyph appears in A1-B2 and the Initial-series number in A3-A5. The student will have little difficulty in picking out the clasped hand in A3, the oval in the top of the head in B3, the fleshless lower jaw in A4, the mouth curl in B4, as the essential characteristic of the cycle, katun, tun, and uinal heads, respectively. The kin head in A5 is the banded-headdress variant (compare fig. 34, _i, j_), and this completes the number, which is 9.17.5.0.0. Reducing this by means of Table XIII to units of the first order, we have: A3 = 9 × 144,000 = 1,296,000 B3 = 17 × 7,200 = 122,400 A4 = 5 × 360 = 1,800 B4 = 0 × 20 = 0 A5 = 0 × 0 = 0 --------- 1,420,200 Deducting from this number all the Calendar Rounds possible, 73 (see Table XVI), and applying rules 1, 2, and 3 (pp. 139, 140, and 141, {180} respectively) to the remainder, the terminal day reached will be found to be 6 Ahau 13 Kayab.