Aristotle now proceeds to enunciate the first of the two Quaternions, and then proceeds to line 30, where the reading of Bekker is irrelevant and unmeaning; but the amendment of Waitz appears to me still worse, being positively incorrect in statement of fact. Waitz reads [Greek: to\ ga\r _e)/stin_ e)ntau=tha] (in the first Quaternion, which has just been enunciated) [Greek: kai\ to\ _ou)k e)/stin_ tô=| a)nthrô/pô| proskei/setai kai\ _tô=| ou)k a)nthrô/pô|_]. These last words are incorrect in fact, for [Greek: ou)k a)/nthrôpos] does not appear in the first Quaternion, but is reserved for the second. While the reading of Waitz is thus evidently wrong, that of Bekker asserts nothing to the purpose. It is useless to tell us merely that [Greek: e)/sti] and [Greek: ou)k e)/stin] attach both to [Greek: di/kaios] and to [Greek: ou) di/kaios] in this first Quaternion ([Greek: e)ntau=tha]), because that characteristic is equally true of the second Quaternion (presently to follow), and therefore constitutes no distinction between the two. To bring out the meaning intended by Aristotle I think we ought here also to retain the words of Bekker, and to add after them some, though not all, of the words of Waitz. The passage would then stand thus--[Greek: to\ ga\r e)/stin e)ntau=tha kai\ to\ ou)k e)/sti tô=| dikai/ô| proskei/setai kai\ tô=| ou) dikai/ô|, kai\ tô=| a)nthrô/pô|, _a)ll' ou)_ tô=| ou)k a)nthrô/pô|.] Or perhaps [Greek: _kai\ ou)_ tô=| ou)k a)nthrô/pô|] might suffice in the last clause (being a smaller change), though [Greek: a)ll' ou)] seem the proper terms to declare the meaning. In the reading which I propose, the sequence intended by Aristotle is clear and intelligible. Having first told us that [Greek: e)/stin] and [Greek: ou)k e)/sti] being joined alternately with [Greek: di/kaios] and with [Greek: ou) di/kaios] and also with [Greek: a)/nthrôpos] and [Greek: ou)k a)/nthrôpos], make up two Quaternions, he proceeds to enunciate the distinctive character belonging to the first Quaternion of the two, viz., that in it [Greek: e)/sti] and [Greek: ou)k e)/stin] are joined both with [Greek: di/kaios] and [Greek: ou) di/kaios], and also with [Greek: a)/nthrôpos] _but not with_ [Greek: _ou)k a)/nthrôpos_], This is exactly the truth.