+------------------------------------+----------+-------------+-------------+ | | | Sun’s Anom. | Moon’s Ano. | | | D. H. M. +-------------+-------------+ | | | s ° ʹ | s ° ʹ | | +----------+-------------+-------------+ | Tab. II. Mean time of New Moon | | | | | in _March_ | 2 8 57 | 8 2 23 | 10 13 32 | | Add, for Lunation, from Tab. VI. | 29 12 44 | 0 29 6 | 0 25 49 | | | -------- | ---------- | ---------- | | Mean New Moon and Anomaly | 31 21 41 | 0 1 29 | 11 9 21 | | To which Time add the Moon’s | +-------------+ | | Ann. Equ. Tab. VIII. | + 0 22 | Equ. Moon’s Anom. - 20 | | And it gives the Mean time | -------- | ---------- | | corrected | 31 22 3 | Anom. cor. 11 9 1 | | From which subtract the Moon’s | | Sun’s Equat. + 1 56 | | elliptic Equ. Tab. X. | - 3 10 | ---------- | | | -------- | Moon’s Ano. 11 10 57 | | And it gives the Mean time equated | 31 18 53 +---------------------------+ | To which add the Sun’s Equation, | | h. m. | | Tab. XI. | + 3 32 | Moon’s ann. Equ. 0 22 add | | And it gives the true time | -------- | Her ellipt. Equ. 3 10 sub.| | of Conjunction | 31 22 25 | Sun’s Equation 3 32 add | | +----------+---------------------------+ | | | Which true time answers to the first of _April_, at 25 minutes past 10 in | | the forenoon: for, as the Astronomical Day begins at Noon, then 22 | | hours 25 min. after the Noon of _March 31_, is _April 1_, at 10 hours | | 25 min. in the Forenoon. | +---------------------------------------------------------------------------+ EXAMPLE II. _To find the time of Full Moon in_ May 1761, _N. S._