_To find the time of New Moon in_ July 1581, _O. S._ From 1781 subtract 200 years, and there remains 1581. +-----------------------------------+-----------+-------------+-------------+ | | | Sun’s Anom. | Moon’s Ano. | | | D. H. M. +-------------+-------------+ | | | s ° ʹ | s ° ʹ | | +-----------+-------------+-------------+ | Table I. Mean time of New Moon | | | | | in _March 1781_ | 13 7 52 | 8 23 37 | 0 0 53 | | Tab. V. Conj. and Anom. for 200 | | | | | years subtract | 8 16 22 | 0 6 42 | 5 0 44 | | | --------- | ---------- | ---------- | | Remain the Conj. and Anom. for | | | | | _March 1581_ | 4 15 30 | 8 16 55 | 7 0 9 | | Tab. VI. Add, for five Lunations, | | | | | to bring it to _July_ | 147 15 40 | 4 25 32 | 4 9 5 | | | --------- | ---------- | ---------- | | The sums are | 152 7 10 | 1 12 27 | 11 9 14 | | +-----------+-------------+ | | The Days in Tab. VII. answer | | Equ. Moon’s Anom. + 13 | | to _July_ 30th | 30 7 10 | ----------- | | Sum of the three Equations | | Anom. cor. 11 9 27 | | subtract | - 7 9 | Sun’s Equat. - 1 16 | | | --------- | ----------- | |True time of Conjunction, _July_ | 30 0 1 | Moon’s Ano. 11 8 11 | | +-----+-----+---------------------------+ | Which is the 30th day, at one minute | Moon’s ann. Eq. 0^h 14^m sub. | | past noon, as shewn by well | Her ellipt. Equ. 3 35 sub. | | regulated Clocks or Watches | Sun’s Equation 3 20 sub. | | | ------------- | | | Sum 7 9 sub. | +-----------------------------------------+---------------------------------+ EXAMPLE II. _To find the time of Full Moon in_ April _A. D. 30, O. S._ From 1730 subtract 1700, and there remains 30.