Sun from Node s ° ʹ To the mean time of Full Moon in _March 1780_, Table III. 10 3 1 Add the distance for 1 Lunation [See _N. B._ Page 195, and Example III, Page 198] 1 0 40 -------- Sum 11 3 41 From which subtract the Sun’s distance from the Node for 2500 years, Table V 5 4 11 -------- Remains the Sun’s distance from the Node, _March 19_, 721 years before CHRIST 5 29 30 To which add 6 Signs for the Moon’s distance, because she was then in opposition to the Sun 6 0 0 -------- The Sum is the Moon’s dist. from the Ascend. Node 11 29 30 That is, she was within half a degree of coming round to it again; and therefore, being so near, she must have been totally, and almost centrally eclipsed. EXAMPLE II _To find the Suns distance from the Node at the Time of New Moon in_ March, _the year before_ CHRIST _424, O. S._ The years 423 added to 1777 make 2200, or 22 Centuries. Sun from Node s ° ʹ At the mean time of New Moon in _March 1777_, Tab. I. 8 23 33 From which subtract the Sun’s distance from the Node for 2200 years, Table V 3 6 0 -------- Remains the Sun’s distance from the Ascending Node, _March 21_, 424 years before CHRIST 5 17 33 Which, taken from 6 Signs, the distance of the Nodes from each other 6 0 0 -------- Leaves the Sun’s distance at that time from the Descending Node, Descending _viz._ 0 12 27 Which being less than 17 degrees, shews that the Sun was then eclipsed. And as from these short Calculations we find those two antient Eclipses taken at a venture, to be truly recorded; it is natural to imagine that so are all the rest in the catalogue. Here follow ASTRONOMICAL TABLES, for calculating the Times of NEW and FULL MOONS and ECLIPSES.