A D the (5½)th, A E the (3⅔)th, A F the (2¾)th, A G the (2⅕)th, A H
the (1⅚)th, A I the (1⁴/₇)th, A K the (1⅜)th, A L the (1²/₉)th, A M
the (1⅒)th, and A B itself the 1st part of A B. The reader may refuse
the language if he likes (though it is not so much in defiance of
etymology as talking of _multiplying_ by ½); but when A B is called 1,
he must either call A F 1/(2¾), or make one definition of one class
of fractions and another of another. Whatever abbreviations they may
choose, all persons will agree that _a_/_b_ is a direction to find such
a fraction as, repeated _b_ times, will give 1, and then to take that
fraction _a_ times.
So, to get 2½/4⅗, the simplest way is to divide the whole unit into 46
parts; 10 of these parts, repeated 4⅗ times, give the whole. The
[Illustration]
4⅗th is then ¹⁰/₄₆, and 2½ such parts is ²⁵/₄₆, or A C. The student
should try several examples of this mode of interpreting complex
fractions.
But what are we to say when the denominator itself is less than unity,
as in 3¼/⅖? Are we to have a (⅖)th part of a unit? and what is it?
Had there been a 5 in the denominator, we should have taken the part
of which 5 will make a unit. As there is ⅖ in the denominator, we must
take the part of which ⅖ will be a unit. That part is larger than a
unit; it is 2½ units; 2½ is that of which ⅖ is 1. The above fraction
then directs us to repeat 2½ units 3¼ times. By extending our word
‘multiplication’ to the taking of a part of a time, all multiplications
are also divisions, and all divisions multiplications, and all the
terms connected with either are subject to be applied to the results of
the other.
If 2⅓ yards cost 3½ shillings, how much does one yard cost? In such a
case as this, the student looks at a more simple question. If 5 yards
cost 10 shillings, he sees that each yard costs ¹⁰/₅, or 2 shillings,
and, concluding that the same process will give the true result when
the data are fractional, he forms 3½/2⅓, reduces it by rules to ³/₂
or 1½, and concludes that 1 yard costs 18 pence. The answer happens
to be correct; but he is not to suppose that this rule of copying for
fractions whatever is seen to be true of integers is one which requires
no demonstration. In the above question we want money which, repeated
2⅓ times, shall give 3½ shillings. If we divide the shilling into 14
equal parts, 6 of these parts repeated 2⅓ times give the shilling. To
get 3½ times as much by the same repetition, we must take 3½ of these 6
parts at each step, or 21 parts. Hence, ²¹/₁₄, or 1½, is the number of
shillings in the price.
APPENDIX V.
ON CHARACTERISTICS.
When the student comes to use logarithms, he will find what follows
very useful. In the mean while, I give it merely as furnishing a rapid
rule for finding the place of a decimal point in the quotient before
the division is commenced.
Public-domain text, read in full here on John Shaqi.
Reviews
Reviews
No reviews yet
Be the first to share your thoughts on this work.
Elsewhere in the archive
Join the Discussion
Join the discussion
Sign in to leave a comment or review.
Sign InorCreate an account