so that the surfaces of equal pressure are similar quadric surfaces,
which, symmetry and dynamical considerations show, must be coaxial
surfaces; and f, g, h vanish, as follows also by algebraical
reduction; and
4c²(c² - a²) / c² - a² \²
[alpha] = ------------[Omega]2² - ( -------[Omega]2 - [eta] )
(c² + a²)² \ c² + a² /
4b²(a² - b²) / a² - b² \²
- ------------[Omega]3² - ( -------[Omega]3 - [zeta] ), (15)
(a² + b²)² \ a² + b² /
with similar equations for [beta] and [gamma].
If we can make
(4[pi][rho]A + [alpha])x² = (4[pi][rho]B + [beta])b²
= (4[pi][rho]C + [gamma])c², (16)
the surfaces of equal pressure are similar to the external case, which
can then be removed without affecting the motion, provided [alpha],
[beta], [gamma] remain constant.
This is so when the axis of revolution is a principal axis, say Oz;
when
[Omega]1 = 0, [Omega]2 = 0, [xi] = 0, [eta] = 0. (17)
If [Omega]3 = 0 or [theta]3 = [zeta] in addition, we obtain the
solution of Jacobi's ellipsoid of liquid of three unequal axes,
rotating bodily about the least axis; and putting a = b, Maclaurin's
solution is obtained of the rotating spheroid.
In the general motion again of the liquid filling a case, when a = b,
[Omega]3 may be replaced by zero, and the equations, hydrodynamical
and dynamical, reduce to
d[xi] 2c² d[eta] 2a²
----- = - -------[Omega]2 [zeta], ------ = -------[Omega]1 [zeta],
dt a² + c² dt a² + c²
d[zeta] 2c²
------- = -------([Omega]2 [xi] - [Omega]2 [eta]) (18)
dt a² + c²
d[Omega]1 a² + c²
--------- = [Omega]2 [zeta] + -------[eta][zeta],
dt a² - c²
d[Omega]2 a² + c²
--------- = [Omega]1 [zeta] + -------[xi][zeta]; (19)
dt a² - c²
of which three integrals are
a²
[xi]² + [eta]² = L - --[zeta]², (20)
c²
(a² + c²)²
[Omega]1² + [Omega]2² = M + ------------ [zeta]², (21)
2c²(a² - c²)
a² + c²
[Omega]1 [xi] + [Omega]2 [eta]N = + ------- [zeta]²; (22)
4c²
and then
/ d[zeta]\² 4c^4
( ------- ) = --------- ([Omega]2[xi] - [Omega]1²[eta])²
\ dt / (a² + c²)
Public-domain text, read in full here on John Shaqi.
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