The reason for the particular shape of shells may not be clear to
all. In the first place all matter has the property known as inertia,
which we may define as that tendency of matter to remain in a state
of rest or to continue at a uniform velocity if in motion. It offers
a resistance to any change in the state of either rest or motion
whether of amount or direction. Consequently when we apply a sudden and
tremendous force to the base of a projectile by means of the expansive
force of exploding powder gases, there will be set up in the metal a
resistance to this force in which every particle of the projectile will
resist by an amount proportional to the mass of particles beyond the
point of application of the force to itself. The actual force will be
proportional to the weight and acceleration produced by the applied
force in the projectile. This explains the reason why the _walls of
the projectile are thicker near the base_. It also explains the method
of calculating the thickness of walls, for if we know the weight at
any cross section and the co-efficient of strength of the metal we may
calculate the thickness of walls necessary to withstand the pressure
for any given muzzle velocity which is fixed by other considerations.
It explains also the preference for steel in projectiles as for the
same weight the steel is much stronger making it possible to throw a
greater amount of shrapnel or high explosives in shell.
[Illustration: _155-MM COMMON STEEL SHELL MK IV_]
The necessity for compact loading, especially in the case of high
explosive shell is also noted as otherwise the shock due to inertia
would break up the charge and perhaps cause a premature explosion.
Hence it is very necessary to guard against airholes in filling shell
cavities.
Public-domain text, read in full here on John Shaqi.
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