Harvard Psychological Studies, Volume 1: Containing Sixteen Experimental Investigations from the Harvard Psychological Laboratory.
Science
Harvard Psychological Studies, Volume 1: Containing Sixteen Experimental Investigations from the Harvard Psychological Laboratory.
Psychology, Experimental
If, in Fig. 2, we have a disc (composed of a green and a red sector)
and a pendulum, moving to the right, and if _P_ represents the
pendulum at the instant when the green sector _AOB_ is beginning to
pass behind it, it follows that some other position farther to the
right, as _P'_, will represent the pendulum just as the last part of
the sector is passing out from behind it. Some part at least of the
sector has been hidden during the entire interval in which the
pendulum was passing from _P_ to _P'_. Clearly the arc _BA'_ measures
the band _BOA'_, in which the green stimulation from the sector _AOB_
is thus at least partially suppressed, that is, on which a relatively
red band is being produced. If the illusion really depends on the
successive eclipse of the sectors by the pendulum, as has been
described, it will be possible to express BA', that is, the width of
a band, in terms of the widths and rates of movement of the two
sectors and of the pendulum. This expression will be an equation, and
from this it will be possible to derive the phenomena which the bands
of the illusion actually present as the speeds of disc and rod, and
the widths of sectors and rod, are varied.
[Illustration: Fig 2.]
Now in Fig. 2 let the
width of the band (_i.e._, the arc BA') = Z
speed of pendulum = r degrees per second;
speed of disc = r' degrees per second;
width of sector AOB (_i.e._, the arc AB) = s degrees of arc;
width of pendulum (_i.e._, the arc BC) = p degrees of arc;
time in which the pendulum moves from P to P' = t seconds.
Now
arc CA'
t = -------;
r
but, since in the same time the green sector AOB moves from _B_ to B',
we know also that
arc BB'
t = -------;
r'
then
arc CA' arc BB'
------- = -------,
r r'
or, omitting the word "arc" and clearing of fractions,
r'(CA') = r(BB').
But now
CA' = BA' - BC,
while
BA' = Z and BC = p;
therefore
CA' = Z-p.
Similarly
BB' = BA' + A'B' = Z + s.
Substituting for _CA'_ and _BB'_ their values, we get
r'(Z-p) = r(Z+s),
or
Z(r' - r) = rs + pr',
or
Z = rs + pr' / r' - r.
It is to be remembered that _s_ is the width of the sector which
undergoes eclipse, and that it is the color of that same sector which
is subtracted from the band _Z_ in question. Therefore, whether _Z_
represents a green or a red band, _s_ of the formula must refer to the
_oppositely colored_ sector, _i.e._, the one which is at that time
being hidden.
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