The next stake would be 3, and if you win you cross out 3, and have
won the six units that you started out to win.
Not infrequently this system, after very nearly proving successful (one
number only being left), goes entirely wrong and runs into very big
figures, and in such a case the player is very lucky if he succeeds in
regaining his losses and winning the six units originally sought for.
More often than not he finds himself obliged to desist through lack of
capital.
The writer's own experience of this system, which he has thoroughly
tested on several occasions at Monte Carlo, was that very frequently
the six units would be won several times in succession with
comparatively slight difficulty--at times, indeed, it appeared almost
ridiculously easy to win. In the end, however, there invariably came a
day when a very contrary state of affairs prevailed, and the money won
returned, with interest, to the bank.
It should be added that before the writer embarked upon his efforts to
defeat the bank at Monte Carlo by means of this system, he gave it a
thorough trial by dealing out the required number of packs of cards at
trente-et-quarante, and noting the results of the various _coups_. In
almost every case the system proved completely successful, as systems
generally do when they are not being played for money.
An exception to this was Lord Rosslyn's defeat by Sir Hiram Maxim, when
the former's system, played for sham money, was beaten at the 3080th
_coup_. Nevertheless the system in question is not a particularly bad
one, were it not that it requires a considerable capital. Ten thousand
units or more are essential, with £16,000 on the basis of a one-louis
unit.
If fortune should favour the player, the profit would be from five to
six hundred louis a day.
The principle of this system is to increase the stakes by one unit
every time, without ever decreasing, until all previous losses are
wiped out and one louis as well is gained for every _coup_ played.
Two exceptions to this rule, however, exist. The first stake is always
"one," but if you lose this, instead of your next stake being two, it
is three; after that it should be four, five, six, seven, eight, etc.,
until your task is accomplished. The game is finished when you can wipe
out all minus quantities from your score sheet and bring the result to
+1. Suppose, therefore, your score sheet shows you to be -3, and your
stake in the ordinary way ought to be 7; instead of staking 7 you would
only stake 4, in order to arrive at the result of +1 if you win. In the
event of your losing the stake of 4, your next stake will be 8, just
as if you had staked 7 in the ordinary course of the game the previous
_coup_. If you lose the 8, you would continue with 9, 10, 11, and so on.
If you win two or three stakes of 1 at the commencement, they are
considered as definite gains, and put away quite apart from your
capital.
In the event of your losing the first two stakes of 1 and 3, your
position is:--
Public-domain text, read in full here on John Shaqi.
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