Lord Kelvin: An account of his scientific life and workGray, Andrew
Science
Lord Kelvin: An account of his scientific life and work
Gray, Andrew
Kelvin, William Thomson, Baron, 1824-1907
[17] Before his death (in 1832) Carnot had obtained a clear
perception of the true state of the case, and of the complete
doctrine of the conservatism of energy. [See extracts from
Carnot's unpublished writings appended, with a biography, to
the reprinted Memoir, by his younger brother, Hippolyte
Carnot.]
[18] This equation for the porous plug experiment may be
established in the following manner, which forms a good example
of Thomson's second definition of absolute temperature. Take
pressure and volume of the gas on the supply side of the plug
as p + dp and v, and on the delivery side as p and v + dv, so
that dp and dv are positive. The net work done in forcing the
gas through the plug = (p + dp)v - p(v + dv) = - pdv + vdp.
Let a heating effect result so that temperature is changed from
T to T + ∂T. Let this be annulled by abstraction of heat
Cp∂T at constant pressure. (Cp = sp. heat press. const.)
[It is to be understood that dv is the total expansion
existing, after this abstraction of heat.] The energy e of the
fluid has been increased by de = - pdv + vdp - Cp∂T.
Now, since the original temperature has been restored, the
same expansion dv if imposed isothermally would involve the
same energy change de; but in that case heat dH (dynamical)
would be absorbed, and work pdv would be done by the gas.
Hence de = dH - pdv. This, with the former value of de, gives
dH = vdp - Cp∂T. Thomson's work-ratio is thus pdv⧸(vdp - Cp∂T).
Now suppose dp imposed without change of volume, and dT to be the
resulting temperature change. The temperature and pressure ratios
are dT⧸T, dp⧸p. Thus dT⧸T = dp dv⧸(vdp - Cp∂T), or
(v⧸T)(dT⧸dv) = 1⧸[1 - (Cp⧸v)(∂T⧸dp)]
which is Thomson's equation. The minus sign on the right arises
from a heating effect having been taken here as the normal
case.
If the temperature T is restored by removing the heat at
constant volume, a similar process gives the equation
(v⧸T)(dT⧸dv) = [1 + (∂T⧸∂p)(∂T⧸dp)]⧸[1 - (Cv⧸v)(∂T⧸dp)]
where dp is the change of pressure before the restoration of
the temperature T, and ∂T⧸∂p is the rate of variation of T
with p, volume constant.
[19] "On a Universal Tendency in Nature to Dissipation of
Energy," _Proc. R.S.E._, 1852, and _Phil. Mag._, Oct., 1852.
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