Manual for the Solution of Military CiphersHitt, Parker
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Manual for the Solution of Military Ciphers
Hitt, Parker
Ciphers; Cryptography
11 11111 41 11111
12 1 42 1
13 1 43 1
14 44 1
15 111111111 45 111111111
16 46
17 1 47
18 111 48 11
19 111 49 111
20 1111 50 11111111
21 1 51
22 11 52 1111
23 111 53 111
24 11 54 11
25 111 55 1
26 1 56 1
27 57
28 11111 58 11111
29 11 59 11
30 60
31 1 61 1
32 11 62 1
33 11 63 1
34 64 1
35 65 1
36 1 66
Each of these tables looks like the normal frequency table except for
the position of 20 and 50 which should represent T, by all our rules,
and should be apparently 30 and 60. But suppose we put the alphabet
and corresponding numerals in this form:
1 2 3 4 5 6 7 8 9 0
1 or 4 A B C D E F G H I J
2 or 5 K L M N O P Q R S T
3 or 6 U V W X Y Z
Then A=11 or 41, J=10 or 40 and T=20 or 50 as we found. Using the
above alphabet, the message may easily be read. Note that this cipher
is made up of ten characters only, the Arabic numerals.
Case 9c--
Message
1156254676 2542294432 1949294015 1423217211 2979703115
4924213511 7424147875 7646252444 5143254845 3179742533
4055461512 7573227945 1627481511 7042351944 1378252149
2514764553 1548342126 7215254075 1611257845 4642217415
4952197929 7015242143 2925444933 1970187531 4079254829
4551491411 7321171554
An examination of this message shows it to consist of forty-four
different two-figure groups running from 11 to 79. Let us prepare a
frequency table of these groups.
Group Frequency
Public-domain text, read in full here on John Shaqi.
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