Newton's Principia : $b The mathematical principles of natural philosophyNewton, Isaac
General
Newton's Principia : $b The mathematical principles of natural philosophy
Newton, Isaac
Celestial mechanics -- Early works to 1800; Mechanics -- Early works to 1800
CASE 1. Let the given points be A, B, C, and Z the fourth point which
we are to find; because of the given difference of the lines AZ, BZ,
the locus of the point Z will be an hyperbola whose foci are A and B,
and whose principal axis is the given difference. Let that axis be MN.
Taking PM to MA as MN is to AB, erect PR perpendicular to AB, and let
fall ZR perpendicular to PR; then from the nature of the hyperbola,
ZR will be to AZ as MN is to AB. And by the like argument, the locus
of the point Z will be another hyperbola, whose foci are A, C, and
whose principal axis is the difference between AZ and CZ; and QS a
perpendicular on AC may be drawn, to which (QS) if from any point Z of
this hyperbola a perpendicular ZS is let fall (this ZS), shall be to AZ
as the difference between AZ and CZ is to AC. Wherefore the ratios of
ZR and ZS to AZ are given, and consequently the ratio of ZR to ZS one
to the other; and therefore if the right lines RP, SQ, meet in T, and
TZ and TA are drawn, the figure TRZS will be given in specie, and the
right line TZ, in which the point Z is somewhere placed, will be given
in position. There will be given also the right line TA, and the angle
ATZ; and because the ratios of AZ and TZ to ZS are given, their ratio
to each other is given also; and thence will be given likewise the
triangle ATZ, whose vertex is the point Z. Q.E.I.
CASE 2. If two of the three lines, for example AZ and BZ, are equal,
draw the right line TZ so as to bisect the right line AB; then find the
triangle ATZ as above. Q.E.I.
[Pg 130]
CASE 3. If all the three are equal, the point Z will be placed in the
centre of a circle that passes through the points A, B, C. Q.E.I.
This problematic Lemma is likewise solved in Apollonius's Book of
Tactions restored by Vieta.
PROPOSITION XXI. PROBLEM XIII.
About a given focus to describe a trajectory that shall pass through
given points and touch right lines given by position.
Let the focus S, the point P, and the tangent TR be given, and suppose
that the other focus H is to be found. On the tangent let fall the
perpendicular ST, which produce to Y, so that TY may be equal to ST,
and YH will be equal to the principal axis. Join SP, HP, and SP will be
the difference between HP and the principal axis. After this manner, if
more tangents TR are given, or more points P, we shall always determine
as many lines YH, or PH, drawn from the said points Y or P, to the
focus H, which either shall be equal to the axes, or differ from the
axes by given lengths SP; and therefore which shall either be equal
among themselves, or shall have given differences; from whence (by the
preceding Lemma), that other focus H is given. But having the foci and
the length of the axis (which is either YH, or, if the trajectory be an
ellipsis, PH + SP; or PH - SP, if it be an hyperbola), the trajectory
is given. Q.E.I.
SCHOLIUM.
Public-domain text, read in full here on John Shaqi.
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