Nitro-Explosives: A Practical TreatiseSanford, P. Gerald (Percy Gerald)
Science
Nitro-Explosives: A Practical Treatise
Sanford, P. Gerald (Percy Gerald)
Celluloid; Explosives
Blasting gelatine (90 per cent. nitro-glycerine and nitro-cellulose) 392
Ammonite (60 per cent. Am(NO_{3}) and 10 per cent. nitro-naphthalene) 310
Gelignite (60 per cent. nitro-gelatine and gun-cotton) 306
Roburite (AmNO_{3} and chloro-nitro-benzol) 294
No. 1 dynamite (75 per cent. nitro-gelatine) 264
Stonite (68 per cent. nitro-gelatine and 32 per cent. wood-meal) 253
Gun-cotton 234
Tonite (gun-cotton and nitrates) 223
Carbonite (25 per cent. nitro-gelatine, 40 per cent. wood-meal,
and 30 per cent. nitrates) 198
Securite (KNO_{3} and nitro-benzol) 183
Gunpowder 143
~Calculation of the Volume of Gas Evolved in an Explosive Reaction.~--The
volume of gas evolved in an explosive reaction may be calculated, but only
when they are simple and stable products, such calculations being made at
0 deg. and 760 mm. Let it be required, for example, to determine the volume of
gas evolved by 1 gram-molecule of nitro-glycerine. The explosive reaction
of nitro-glycerine may be represented by the equation.
C_{3}H_{5}O_{3}(NO_{2})_{3} = 3CO_{2} + 2-1/2H_{2}O + 1-1/2N_{2} + 1/4O_{2}
By weight 227 = 132 + 45 + 42 + 8
By volume 2 = 3 + 2-1/2 + 1-1/2 + 1/4
The weights of the several products of the above reactions are calculated
by multiplying their specific gravities by the weight of 1 litre of
hydrogen at 0 deg. C. and 760 mm. (0.0896 grm). Thus,
One litre of CO_{2} = 22 x .0896 = 1.9712 grm.
" H_{2}O = 9 x " = 0.8064 "
" N_{2} = 14 x " = 1.2544 "
" O_{2} = 16 x " = 1.4336 "
The volume of permanent gases at 0 deg. and 760 mm. is constant, and assuming
the gramme as the unit of mass, is found to be 22.32 litres. Thus:--
Volume of 44 of CO_{2}, at 0 deg. and 760 mm. = 44/1.9712 = 22.32 litres.
18 " H_{2}O " " = 18/0.8044 = 22.32 "
28 " N_{2} " " = 28/1.2544 = 22.32 "
32 " O_{2} " " = 32/1.4366 = 22.32 "
Therefore
132 grms. of CO_{2} at 0 deg. C and 760 mm. = 22.32 x 3 = 66.96 litres.
45 " H_{2}O " " = 22.32 x 2-1/2 = 55.80 "
42 " N_{2} " " = 22.32 x 1-1/2 = 33.48 "
8 " O_{2} " " = 22.32 x 1/4 = 5.58 "
____________
161.82 "
Therefore 1 gram-molecule or 227 grms. of nitro-glycerine when exploded,
produces 161.82 litres of gas at 0 deg. C and 760 mm.
Public-domain text, read in full here on John Shaqi.
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