The Canterbury Puzzles, and Other Curious ProblemsDudeney, Henry Ernest
Science
The Canterbury Puzzles, and Other Curious Problems
Dudeney, Henry Ernest
Puzzles; Riddles
In this case Sir Hugh had greatly perplexed his chief builder by
demanding that he should make a window measuring one foot on every side
and divided by bars into eight lights, having all their sides equal. The
illustration will show how this was to be done. It will be seen that if
each side of the window measures one foot, then each of the eight
triangular lights is six inches on every side.
"Of a truth, master builder," said De Fortibus slyly to the architect, "I
did not tell thee that the window must be square, as it is most certain
it never could be."
37.--_The Crescent and the Cross._
"By the toes of St. Moden," exclaimed Sir Hugh de Fortibus when this
puzzle was brought up, "my poor wit hath never shaped a more cunning
artifice or any more bewitching to look upon. It came to me as in a
vision, and ofttimes have I marvelled at the thing, seeing its exceeding
difficulty. My masters and kinsmen, it is done in this wise."
[Illustration]
The worthy knight then pointed out that the crescent was of a particular
and somewhat irregular form--the two distances _a_ to _b_ and _c_ to _d_
being straight lines, and the arcs _ac_ and _bd_ being precisely similar.
He showed that if the cuts be made as in Figure 1, the four pieces will
fit together and form a perfect square, as shown in Figure 2, if we there
only regard the three curved lines. By now making the straight cuts also
shown in Figure 2, we get the ten pieces that fit together, as in Figure
3, and form a perfectly symmetrical Greek cross. The proportions of the
crescent and the cross in the original illustration were correct, and
the solution can be demonstrated to be absolutely exact and not merely
approximate.
I have a solution in considerably fewer pieces, but it is far more
difficult to understand than the above method, in which the problem is
simplified by introducing the intermediate square.
38.--_The Amulet._
The puzzle was to place your pencil on the A at the top of the amulet and
count in how many different ways you could trace out the word
"Abracadabra" downwards, always passing from a letter to an adjoining
one.
A
B B
R R R
A A A A
C C C C C
A A A A A A
D D D D D D D
A A A A A A A A
B B B B B B B B B
R R R R R R R R R R
A A A A A A A A A A A
"Now, mark ye, fine fellows," said Sir Hugh to some who had besought him
to explain, "that at the very first start there be two ways open:
whichever B ye select, there will be two several ways of proceeding
(twice times two are four); whichever R ye select, there be two ways of
going on (twice times four are eight); and so on until the end. Each
letter in order from A downwards may so be reached in 2, 4, 8, 16, 32,
etc., ways. Therefore, as there be ten lines or steps in all from A to
the bottom, all ye need do is to multiply ten 2's together, and truly the
result, 1024, is the answer thou dost seek."
39.--_The Snail on the Flagstaff._
Public-domain text, read in full here on John Shaqi.
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