The Catholic World, Vol. 03, April to September, 1866Various
Religion
The Catholic World, Vol. 03, April to September, 1866
Various
Catholic Church -- Periodicals
_Ordnance and Targets_.--The Admiralty having erected a new target,
representing a portion of the side of the _Hercules_, experiments were
made at Shoeburyness which proved that a thickness of armor casing had
been attained which afforded perfect security against even the largest
guns recently constructed. The target has a facing of {138} 9-inch
armor-plates, and contains altogether eleven inches thickness of iron.
Against this three 12-ton shunt guns were fired, at a distance of only
200 yards, with charges varying from 45 lbs. to 60 lbs. of powder. One
steel shot, of 300 lbs. weight, 10-1/2 inches in diameter, fired with
60 lbs. of powder, at a velocity of 1,450 feet per second, barely
broke through the armor, without injuring the backing. Sir William
Armstrong has expressed his conviction, in the _Times_, that the
600-pounder gun will be unable to penetrate this target, and that it
will, in fact, require a gun carrying 120 lbs. of powder and steel
shot to pierce this massive shield. Mr. W. C. Unwin has pointed out,
in a letter to the _Engineer_, that for similar guns with shot of
similar form, and charges in a constant ratio to the weight of the
shot, the velocity is nearly constant. Then, assuming the resistance
of the plates to be as the squares of their thicknesses, it follows
that when the diameter of the shot increases, as well as the thickness
of the armor, the maximum thickness perforated will (by theory) vary
as the cube root of the weight of the shot, or, in other words, as the
calibre of the gun; and the weight of the shot necessary to penetrate
different thicknesses of armor will be as the cubes of those
thicknesses. The ratio deduced from the Shoeburyness experiments is
somewhat less than this, being as the 2.5 power and the 5.2 power
respectively. Practical formula deduced from experiments are given,
which agree with Sir William Armstrong's conclusion, and prove that a
gun which can effectively burn a charge of at least 100 lbs. of powder
will be required to effectually penetrate the side of the _Hercules_.
Public-domain text, read in full here on John Shaqi.
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