The Elements of Qualitative Chemical Analysis, vol. 1, parts 1 and 2.: With Special Consideration of the Application of the Laws of Equilibrium and of the Modern Theories of Solution.Stieglitz, Julius
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The Elements of Qualitative Chemical Analysis, vol. 1, parts 1 and 2.: With Special Consideration of the Application of the Laws of Equilibrium and of the Modern Theories of Solution.
Stieglitz, Julius
Chemistry, Analytic -- Qualitative
When the ionization of aluminium hydroxide, as an acid, is
considered to take place according to Al(OH)_{3} ⇄ AlO_{2}^{−} +
H^{+} + H_{2}O, which agrees best with its real behavior (p.
172), we can find, similarly, that [Al^{3+}] + [AlO_{2}^{−}] is
a ‹minimum›, when aluminium hydroxide is precipitated in such a
way, that an excess ‹x› of the hydroxide-ion is used, and ‹x› =
[HO^{−}] = (3 K_{HOH} × K_{Bas.S.P.} / K_{Ac.S.P.})^{0.25},—where
K_{Ac.S.P.} represents the solubility-product constant for
[AlO_{2}^{−}] × [H^{+}]. That a minimum loss of aluminium hydroxide
would be suffered when the favorable excess of the hydroxide-ion
(‹x›) is calculated on the basis of the equation as given, may
readily be seen by again assuming definite values for K_{Bas.S.P.}
and K_{Ac.S.P.}. It also appears that this minimum loss[394] of
aluminium includes one-third as many Al^{3+} ions, as AlO_{2}^{−}
ions—a relation corresponding, again, to a saturated solution of
aluminium aluminate, Al(AlO_{2})_{3}.
FOOTNOTES:
[354] When all three of the hydrogen atoms in the hydroxide
are ionized, an aluminate ion, AlO_{3}^{3−} is formed:
Al(OH)_{3} ⇄ AlO_{3}^{3−} + 3 H^{+}. But, as in the case of
other weak polybasic acids, a single hydrogen atom is far more
readily ionized than are the remaining two (p. 102), and the ion
Al(OH)_{2}O^{−}, which is formed by the ‹primary› ionization,
readily loses water and forms the anhydride ion AlO_{2}^{−}. The
most important aluminates are derivatives of this ion.
[355] See the table at the back of Smith's ‹Inorganic Chemistry›,
or p. 149 of Remsen's ‹Inorganic Chemistry›.
[356] The displacement of hydrogen by a metal, like sodium, is the
result of the displacement of the ‹hydrogen-ion› (see Chapters XIV
and XV). The hydrogen-ion in fused sodium hydroxide is probably
formed chiefly by the secondary ionization of the hydroxide-ion
(HO^{−} ⇄ H^{+} + O^{2−}) (see Chap. XIII). We cannot have positive
ions, Na^{+}, with negative ions, O^{2−}, without having some
ions NaO^{−}. (O^{2−} + Na^{+} ⥂ NaO^{−}), NaOH, undoubtedly,
is much ‹too› ‹weak› an ‹acid› to form salts with bases in the
presence of water. Such salts would be decomposed by water (see
below, p. 180), as sodium oxide, indeed, is decomposed; we have
Na—O—Na + HOH ⇄ 2 NaOH (see Chapter XIII for a detailed discussion
of this action). These relations sufficiently account for the fact
that salts of sodium hydroxide, in which it has the functions of an
acid, are not commonly formed. (‹Cf.› Abegg, ‹Anorganische Chemie›,
II, (1) p. 247.)
[357] See J. J. Thomson, ‹Corpuscular Theory of Matter›, pp.
103–141.
[358] See Mendeléeff, ‹Principles of Chemistry›, I, 22 (1891), in
regard to the rôle of "even" and "uneven" series in the system.
[359] In regard to the indications of the amphoteric character of
stronger acids, see Chapter XV.
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