The Elements of Qualitative Chemical Analysis, vol. 1, parts 1 and 2.: With Special Consideration of the Application of the Laws of Equilibrium and of the Modern Theories of Solution.Stieglitz, Julius
Science
The Elements of Qualitative Chemical Analysis, vol. 1, parts 1 and 2.: With Special Consideration of the Application of the Laws of Equilibrium and of the Modern Theories of Solution.
Stieglitz, Julius
Chemistry, Analytic -- Qualitative
When potassium cyanide is added to the deep blue ammoniacal
solution of cupric-ammonium sulphate [Cu(NH_{3})_{4}]SO_{4}, the
cupric-ion is reduced[453] [p229] to cuprous-ion, and the latter
is converted, by an excess of cyanide, into the extremely stable
complex ion Cu(CN)_{3}^{2−} and its salt, potassium cuprocyanide
K_{2}[Cu(CN)_{3}]. The instability constant of the complex ion
is: [Cu^{+}] × [CN^{−}]^3 / [Cu(CN)_{3}^{2−}] = 0.5E−27, and
the concentration of cuprous-ion, in a 0.1 molar solution, is
approximately[454] 3.7E−8. Without an excess of cyanide, traces of
cuprous sulphide may still be precipitated, but ‹a few drops excess
will prevent the precipitation entirely›.[455]
With an excess of potassium cyanide, cadmium forms the salt
K_{2}[Cd(CN)_{4}], yielding the ion [Cd(CN)_{4}^{2−}]. The
instability constant[456] of the complex ion is [Cd^{2+}] ×
[CN^{−}]^4 / [Cd(CN)_{4}^{2−}] = 1.4E−17. The concentration of
cadmium-ion, in a 0.1 molar solution of the salt, is then
approximately[457] 8E−5.
If potassium cyanide is added to an ammoniacal solution, containing
both cadmium and copper, until the color of the solution is just
discharged, and if two or three drops excess of the cyanide is then
used, the addition of ammonium sulphide will precipitate pure cadmium
sulphide (‹exp.›), while ammonium sulphide, added to a portion of
the original ammoniacal solution, will precipitate a dark mixture
of cupric and cadmium sulphide (‹exp.›), in which the yellow color
of cadmium sulphide is masked by the black precipitate of cupric
sulphide.
«Cobalticyanide and Nickelocyanide Ions.»—In much the same way, in
the identification of nickel in the presence of cobalt, advantage
may be taken of the fact that cobalt forms an extremely stable
cobalticyanide[458] ion, [Co(CN)_{6}^{3−}], which does not permit of
the precipitation of cobaltic hydroxide, whereas nickel does not form
such an ion, but only forms a not very stable nickelocyanide ion,
[Ni(CN)_{4}^{2−}], which is readily decomposed by bromine and alkali,
nickelic hydroxide being precipitated. [p230] The following are the
chief actions involved in the precipitation of the latter:[459]
Ni(CN)_{4}^{2−} ⥂ Ni^{2+} + 4 CN^{−}
2 Ni^{2+} + Br_{2} ⥂ 2 Ni^{3+} + 2 Br^{−}
Ni^{3+} + 3 HO^{−} ⥂ Ni(OH)_{3} ↓
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