The Principles of Chemistry, Volume IIMendeleyev, Dmitry Ivanovich
Science
The Principles of Chemistry, Volume II
Mendeleyev, Dmitry Ivanovich
Argon; Chemistry; Periodic law
In 1850-60 Wöhler and Buff obtained an alloy of silicon and
magnesium by the action of sodium on a molten mixture of magnesium
chloride, sodium silicofluoride, and sodium chloride. The sodium
then simultaneously reduces the silicon and magnesium.
Friedel and Ladenburg subsequently prepared silicon hydride in a
pure state, and showed that it is not spontaneously inflammable in
air, at the ordinary pressure, but that, like PH_{3}, and like the
mixture prepared by the above methods, it easily takes fire in air
under a lower pressure or when mixed with hydrogen. They prepared
the pure compound in the following manner: Wöhler showed that when
dry hydrochloric acid gas is passed through a slightly heated tube
containing silicon it forms a very volatile colourless liquid,
which fumes strongly in air; this is a mixture of silicon chloride,
SiCl_{4}, and _silicon chloroform_, SiHCl_{3}, which corresponds
with ordinary chloroform, CHCl_{3}. This mixture is easily
separated by distillation, because silicon chloride boils at 57°,
and silicon chloroform at 36°. The formation of the latter will be
understood from the equation Si + 3HCl = H_{2} + SiHCl_{3}. It is
an anhydrous inflammable liquid of specific gravity 1·6. It forms a
transition product between SiH_{4} and SiCl_{4}, and may be
obtained from silicon hydride by the action of chlorine and
SbCl_{5}, and is itself also transformed into silicon chloride by
the action of chlorine. Gattermann obtained SiHCl_{3} by heating
the mass obtained after the action (Note 4) of Mg upon SiO_{2}, in
a stream of chlorine (with HCl) at about 470°. Friedel and
Ladenburg, by acting on anhydrous alcohol with silicon chloroform,
obtained an ethereal compound having the composition
SiH(OC_{2}H_{5})_{3}. This ether boils at 136°, and when acted on
by sodium disengages silicon hydride, and is converted into ethyl
orthosilicate, Si(OC_{2}H_{5})_{4}, according to the equation
4SiH(OC_{2}H_{5})_{3} = SiH_{4} + 3Si(OC_{2}H_{5})_{4} (the sodium
seems to be unchanged), which is exactly similar to the
decomposition of the lower oxides of phosphorus, with the evolution
of phosphuretted hydrogen. If we designate the group C_{2}H_{5},
contained in the silicon ethers by Et, the parallel is found to be
exact:
4PHO(OH)_{2} = PH_{3} + 3PO(OH)_{3};
4SiH(OEt)_{3} = SiH_{4} + 3Si(OEt)_{4}.
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