A Budget of Paradoxes, Volume IIDe Morgan, Augustus
Philosophy
A Budget of Paradoxes, Volume II
De Morgan, Augustus
Circle-squaring; Perpetual motion; Science -- Miscellanea; Trisection of angle
be abbreviated into a/b+ c/d+ e/f+ etc.: each fraction being understood as
falling down to the side of the preceding sign +. In every such fraction we
may suppose b, d, f, etc. {368} positive; a, c, e, &c. being as required:
and all are supposed integers. If this succession be continued ad
infinitum, and if a/b, c/d, e/f, etc. all lie between -1 and +1, exclusive,
the limit of the fraction must be incommensurable with unity; that is,
cannot be A/B, where A and B are integers.
First, whatever this limit may be, it lies between -1 and +1. This is
obviously the case with any fraction p/(q + [omega]), where [omega] is
between +-1: for, p/q, being < 1, and p and q integer, cannot be brought up
to 1, by the value of [omega]. Hence, if we take any of the fractions
a/b, a/b+ c/d, a/b+ c/d+ e/f, etc.
say a/b+ c/d+ e/f+ g/h we have, g/h being between +-1, so is e/f+ g/h, so
therefore is c/d+ e/f+ g/h; and so therefore is a/b+ c/d+ e/f+ g/h.
Now, if possible, let a/b+ c/d+ etc. be A/B at the limit; A and B being
integers. Let
P = A c/d+ e/f+ etc., Q = P e/f+ g/h+ etc., R = Q g/h + i/k + etc.
P, Q, R, etc. being integer or fractional, as may be. It is easily shown
that all must be integer: for
{369}
A/B = a/b+ P/A, or, P = aB - bA
P/A = c/d+ Q/P, or, Q = cA - dP
Q/P = e/f+ R/Q, or, R = eP - fQ
etc., etc. Now, since a, B, b, A, are integers, so also is P; and thence Q;
and thence R, etc. But since A/B, P/A, Q/P, R/Q, etc. are all between -1
and +1, it follows that the unlimited succession of integers P, Q, R, are
each less in numerical value than the preceding. Now there can be no such
_unlimited_ succession of _descending_ integers: consequently, it is
impossible that a/b+ c/d+, etc. can have a commensurable limit.
It easily follows that the continued fraction is incommensurable if a/b,
c/d, etc., being at first greater than unity, become and continue less than
unity after some one point. Say that i/k, l/m,... are all less than unity.
Then the fraction i/k+ l/m+ ... is incommensurable, as proved: let it be
[kappa]. Then g/(h + [kappa]) is incommensurable, say [lambda]; e/(f +
[lambda]) is the same, say [mu]; also c/(d + [mu]), say [nu], and a/(b +
[nu]), say [rho]. But [rho] is the fraction a/b+ c/d+ ... itself; which is
therefore incommensurable.
Let [phi]z represent
a a^2 a^3
1 + - + ------- + -------------- + ....
z 2z(z+1) 2.3.z(z+1)(z+2)
{370} Let z be positive: this series is convergent for all values of a, and
approaches without limit to unity as z increases without limit. Change z
into z + 1, and form [phi]z - [phi](z+1): the following equation will
result--
a
[phi]z-[phi](z+1) = ------([phi](z+2))
z(z+1)
a [phi](z+1) a [phi](z+1) a [phi](z+2)
or a = - ---------- . z + - ---------- . --- ----------
z [phi]z z [phi]z z+1 [phi](z+1)
a = [psi]z(z+[psi](z+1))
Public-domain text, read in full here on John Shaqi.
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