These circumstances considered, the space requisite for the interments in a town may be determined by the multiplication of the average square superficies of a grave, by the average yearly mortality, and the period of years which the grave is to remain closed. “As an example,” says Dr. Reicke, “of the mode of calculating the necessary space for the burial ground of a populous district, I will take a town of 35,000 inhabitants. Accordingly of this number it may be reckoned there will yearly die 1000. Of the number 500 will be adults, 50 children, from 7 to 14, and 450 children from 0 to 7 years. For the adults, allowing more than the most economical space, I calculate graves of 48 square feet Wirtemburg (_i. e._ 54·72 square feet English); for the children between 7 and 14 years, 24 square feet (27·36 English feet); and for those under 7, 20 square feet (22·80 English). For the adults I take a period of 10 years, for the youth 8 years, for the infants 7 years, as the time during which periods the grave must not be opened.” According to this calculation the space required for the interment of the several classes would be— English Numbers English Square Dead. Years. Square Feet. Feet. 1. Adults. 54·72 × 500 × 10 = 273,600 2. Youth. 27·36 × 50 × 8 = 10,944 3. Infants. 22·80 × 450 × 7 = 71,820 ——————— Total 356,364 “According to the usual calculation the requisite space would be:— 39·90 × 1,000 × 10 = 399,000. So that, by the above calculation and classification, there is a saving of 42,636 square feet. “I must, however, beg to be understood that this calculation is only meant to serve as an example, and that the factors on which it is grounded must undergo the necessary variations, according as the soil is more or less favourable to decomposition, and therefore requiring a longer or shorter period of rest; and according to the greater or less consistency of the soil, and therefore requiring the space between the graves to be greater or less; and, lastly, according as the average mortality varies, and especially the rate of mortality of the three classes of ages.” These factors would give different results for different populations, according to their different proportions of death. As an example of a town population, in Whitechapel the proportion of deaths for every 35,000 of the population will be 1125 deaths yearly. As an example of a rural population, for every 35,000 of the population in Hereford, there will only be 562 deaths annually, and the space required for interments for the two populations will be as follows, at the actual rate of deaths per 35,000 amongst the population in the Whitechapel Union in 1839: