(65.) The bodies impinging were, in the last case, supposed to move in
the same direction. We shall now consider the case in which they move
in opposite directions.
First, let the masses A and B be supposed to be equal, and moving in
opposite directions, with the same velocity. Let C, _fig. 5._, be
the point at which they meet. The equal motions in opposite directions
will, in this case, destroy each other, and both masses will be
reduced to a state of rest. Thus, the mass A loses all its motion in
the direction A C, which it may be supposed to transfer to B at
the moment of impact. But B having previously had an equal quantity
of motion in the direction B C, will now have two equal motions
impressed upon it, in directions immediately opposite; and these
motions neutralising each other, the mass becomes quiescent. In this
case, therefore, as in all the former examples, each body transfers
to the other all the motion which it loses, consistently with the
principle of “action and reaction.”
The masses A and B being still supposed equal, let them move towards
C with different velocities. Let A move with the velocity 10, and B
with the velocity 6. Of the 10 parts of motion with which A is endued,
6 being transferred to B, will destroy the equal velocity 6, which B
has in the direction B C. The bodies will then move together in
the direction C B, the four remaining parts of A’s motion being
equally distributed between them. Each body will, therefore, have two
parts of A’s original motion, and 2 therefore will be their common
velocity after impact. In this case, A loses 8 of the 10 parts of its
motion in the direction A C. On the other hand, B loses the entire
of its 6 parts of motion in the direction B C, and receives 2
parts in the direction A C. This is equivalent to receiving 8
parts of A’s motion in the direction A C. Thus, according to the
law of “action and reaction,” B receives exactly what A loses.
Finally, suppose that both the masses and velocities of A and B are
unequal. Let the mass of A be 8, and its velocity 9: and let the mass
of B be 6, and its velocity 5. The quantity of motion of A will be 72,
and that of B, in the opposite direction, will be 30. Of the 72 parts
of motion, which A has in the direction A C, 30 being transferred
to B, will destroy all its 30 parts of motion in the direction
B C, and the two masses will move in the direction C B, with
the remaining 42 parts of motion, which will be equally distributed
among their 14 component masses. Each component part will, therefore,
receive 3 parts of motion; and accordingly 3 will be the common
velocity of the united mass after impact.
Public-domain text, read in full here on John Shaqi.
Reviews
Reviews
No reviews yet
Be the first to share your thoughts on this work.
Join the Discussion
Join the discussion
Sign in to leave a comment or review.
Sign InorCreate an account