Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.Baldwin, Thomas
History
Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.
Baldwin, Thomas
Aeronautics -- Early works to 1900; Balloons -- Early works to 1800
401. 10th. Step. Subtract the _Height_ in Feet, corresponding to the
_Expansion_ on .0892 Tenths of an Inch, (_less_ than Inches 24.2
Tenths, of the _upper_ barometric Tube,) from the _Height_, in Feet,
corresponding to _the Expansion on_ Inches 24.1 Tenth of the same
barometric Tube, continuing at the Standard Heat,[129]
viz. 7388.0
95.9
——————
The Remainder 7292.1 gives the real, viz. the _less_ Height of the
_upper_ Barometer, at 24.1892 with the Standard Temperature.
Repeat the same Process, viz. the 9th. and 10th. Steps, for the _lower_
Barometer, thus:
For the lower Barometer in the 2d. Example.
First, Find the Height, in _Feet_, of the lower Barometer, standing
at Inches 28.1318 Tenths, in the 2d. Column of the 2d. Table,
corresponding to Inches and Tenths of the Quicksilver in the barometric
Tube, in the first Column of the same Table, thus:
The lower Barometer standing at 28.1318; it must be considered, where
in the 2d. Column of the 2d. Table, a Height corresponding to such
Inches and Tenths can lye: and the Answer is, somewhere above 28
Inches, .1 Tenth, but not so high as 28 Inches .2 Tenths: 28.1318
Tenths being more than 28 Inches .1 Tenth, yet less than 28 Inches .2
Tenths.
First, then, look, in the first Column for 28.1, and the corresponding
Height, in Feet, is 3386.6:
but the Height for 28.2, is only 3294.0:
——————
subtracting the less from the greater;
the Remainder is 92.6,
the same as in the 3d. Column, viz. the Height, in Feet and Tenths,
corresponding to _one Tenth only_ above 28.1.
Having therefore found that Feet 92.6 Tenths, are the Height,
corresponding to one Tenth only above Inches 28.1 Tenth, of the lower
Barometer, with the Temperature of freezing; for which _sole_ Purpose,
the 2d Table is calculated;—a new Question arises, viz. what are the
Heights, in Feet and Tenths, corresponding to the remaining Decimals
above 28.1, viz.
.03
.001
.0008; to be resolved by Application of the third Table, or Table for
Tenths, which see, (in Section 373.)
Look in the 3d. Table, with 92, (omitting the .6 as too minute) and with
3 answering to .03, which gives 28 = Feet 28.
1 to .001, 9 = .9
8 to .0008, 74 = .74
——————
29.6|4
Which 29.6 is the _Height_ in Feet and Tenths corresponding to .0318
Tenths above Inches 28.1 Tenth: and Inches 28.1 Tenth gave Feet 3386.6
Tenths in Height: therefore an additional Height of so many Tenths or
Decimals of an Inch of Quicksilver in the Tube of the Barometer, must
give in Feet, a _less_ Height of the _lower_ Barometer, elevated above
the _imaginary_ Level indicated by the Quicksilver resting in the Tube
at 32 Inches.[130]
Public-domain text, read in full here on John Shaqi.
Reviews
Reviews
No reviews yet
Be the first to share your thoughts on this work.
Elsewhere in the archive
Join the Discussion
Join the discussion
Sign in to leave a comment or review.
Sign InorCreate an account