Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.Baldwin, Thomas
History
Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.
Baldwin, Thomas
Aeronautics -- Early works to 1900; Balloons -- Early works to 1800
399. 8th Step. Subtract the latter from the former and the Remainder
is 107.9, the same as in the 3d Column: viz. the Height, in Feet and
Tenths, corresponding to one Tenth only, namely, the ist Tenth above
Inches 24, .1 Tenth: with the Temperature of 31.24 of Farenheit, for
which sole Purpose the 2d Table is calculated.
A new Question _then_ arises, viz. what are the Heights in Feet and
Tenths, corresponding to the remaining Tenths or Decimals of an Inch
above Inches 24, .1 Tenth,
viz. .08
.009
.0002? which is to be resolved, by Application of the 3d Table,
or Table for _Tenths_, which see, (Section 373.)
[Sidenote: _9th Step._]
400. _9th Step applied in the 2d. Example._
First for the _upper_ Barometer.
Look in the Table for Tenths, in the left vertical Column with 107,
(rejecting the .9, as too minute;) and along the horizontal Line at the
top, with 8: and find the Answer _gradually_, thus:
1st. With 107, and 8, (as a whole Number,) answering to .08: which, in
the Place of Meeting, gives 86 Feet.
2d. With 107, and 9, (as a whole Number,) answering to .009: which, in
the Place of Meeting, gives 97.
3d. With 107, and 2, (as a whole Number,) answering to 0002: which, in
the Place of Meeting, gives 21.
Place them in View, and add, and bring them back again into Decimals,
thus:
With 107 and 8, answering to .08 giving 86. Feet
and 9, to .009 9.7
and 2, to .0002 .21
—————
95.9|1
(Next: with the 9, _if required_; which was before rejected:) but there
being no .9 Tenths in the left Vertical, call it 90, and allow for it
in each Answer by moving the decimal Point two Places to the left,
thus: with
90, and 8, answering to .08 giving 72 = .72
and 9, to .009 81 = .081
and 2, to .0002 18 = .0018
————
To .8|00|28
Add the former Sum 95.9|
—————
Total = 96.7)
Which 95.9 is the _Height_ in Feet and Tenths corresponding to .0892
Decimals of an Inch above Inches 24 .1 Tenth: and 24 .1 gave Feet
7388.0 in _Height_; therefore an additional _Height_, of so many Tenths
of an Inch of Quicksilver in the Tube of the Barometer, must give in
Feet, a _less_ Height of the Barometer elevated above the _imaginary_
Level indicated at 32 Inches.
[Sidenote: _10th. Step._]
Public-domain text, read in full here on John Shaqi.
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