204.1 = the same 204.1 612.3 = becomes 61.23 204.1 = 2.041 340.1 = .3401 68.0 = .00680 ————————— viz. Expansion of Air _with_} 267.7|179 28° _on_ 3935.1 } 408. _Second_, _with_ .71° _on_ Feet 3000 = 517.5 900 as 9000 = 1552.7 30 3000 = 517.5 5 5000 = 862.6 .1 1000 = 172.5 In order to decimate these Answers, it must be observed that the Expansion was not _with_ 71 Degrees, but with .71 _Tenths_ of a Degree of Heat; therefore the decimal Point corresponding to 3000 Feet in the Question, must in the Answer be removed _two_ Places to the left, thus: 517.5 becomes 5.175: for the 100, three Places: for 1.5527 the 10, _four_ Places: and so .05175 on. .008626 .0001725 —————————— 6.7|882485 The Expansion with .71 being found, viz. Feet 6.7 Tenths; add it to the Expansion on 28 Feet already found, viz. 267.7 ————— 274.4 Answer. Which _Height_ in Feet and Tenths, corresponding to the _Expansion_ of Air with 28°.71 Tenths of a Degree of Heat more than the Standard 31°.24, being added to the _Height_ in Feet and Tenths, corresponding to the _Expansion on Inches_ of the Quicksilver in the _upper_ Barometer, with the Standard-Heat, already found, viz. 3935.1 gives the _real Height_ of the _Mountain_, 274.4 —————— or _upper Station_, sought. 4209.5 END OF THE THIRD STAGE. * * * * * _The second Example_ briefly _stated: referring to the Sections._ [Sidenote: Section, 391.] 409. Below: Barometer 28.1318. Attached Thermometer 61°.8; Air ditto 63.9. Above: Barom. 24.178. Attached Thermometer 57°.2; Air ditto 56°. Degrees of Heat, viz. 4°.6 to be added to the _colder_ Barometer at Inches 24.178 Tenths, by the first Table, viz. .0112 Parts of an Inch of the Quicksilver in the Barometer, raised by 4°.6 of Heat. ——————— The Sum 24.1892 is the +point+, in Inches and Tenths of an Inch, at which the upper Barometer _now_ rests, being of _equal_ Heat with the lower. _End of the first Stage._ [Sidenote: Section, 399.] By the 2d. Table, find the _Height_, in Feet and Tenths, corresponding to the _said_ +point+ when at the Standard-Heat; gradually, thus: the _Height_ corresponding to Feet 24.1 is 7388.0: then with the Difference 107.9, (rejecting the .9). [Sidenote: Section, 400.]