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Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.Baldwin, Thomas

History

Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.

Name: Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.
Author: Baldwin, Thomas

Baldwin, Thomas

Aeronautics -- Early works to 1900; Balloons -- Early works to 1800

Find the Height by the 3d. Table corresponding to
      .08       86.0 }
      .009       9.7 } = Feet 95.9 Tenths.
      .0002       .2 }

  Which Height subtract from  7388.0
                                95.9
                              ——————
  And there remains, in Feet, 7292.1

The Height corresponding to Inches 24.1892 Tenths of the _upper_
Barometer, with the Standard Temperature of 31.24; for which sole
Purpose the 2d. Table is calculated.

Repeat the last Process with the _lower_ Barometer, resting at 28.1318,
gradually, thus:

[Sidenote: Section, 401.]

By the 2d. Table, find the _Height_ corresponding to 28.1, which is
3386.61; then with the Difference 92.6 (rejecting the .6) find the
corresponding _Height_, by the 3d. Table for the remaining Tenths or
Decimals of an Inch, above 28.1, viz.
  .03      28.0 }
  .001       .9 } = Feet 29.6 Tenths.
  .0008      .7 }

[Sidenote: Section 402.]

  Which _Height_ subtract from 3386.6
                                 29.6
                               ——————
          And there remains,   3357.0 viz. the _Height_ in Feet
corresponding to Inches 28.1318 Tenths of the lower Barometer, with the
Standard Temperature of 31.24, for which sole Purpose the 2d. Table is
calculated.

[Sidenote: Section 403.]

Subtract the _Height_ in Feet, corresponding to Inches of Quicksilver
in the upper Barometer,
  viz. 7292.1 from ditto in _lower_ Barometer,
  viz. 3357.0 and there remains the _Height_ in Feet
       —————— of the upper Barometer at the Standard-Temperature
  viz. 3935.1 of 31.24.

                      _End of the second Stage._

[Sidenote: Section, 404.]

On which Number of Feet, viz. 3935.1, by the 4th Table, find the
_Height_, with 28°.71 of Heat:
    _With_ 28°.   _on_ Feet 3935.1 = 267.7 and
    _With_    .71 _on_ the same    =   6.7
                                     —————
                             Sum     274.4: which
  Height, more than the Standard-Heat,
  being _added_ to                  3935.1
  the Height, with the Standard,    ——————
  gives the true Height, viz.       4209.5.

                       _End of the third Stage._




                            CHAPTER LXXVII.


                    PRACTICE OF THE THIRD EXAMPLE,

                    REFERRING TO THE SECTIONS.[132]

Section 410. _Below_: Barom. Inches 30, .0168:
  Attached Therm.       60°.6;    Air-ditto, 60°.2:
  _Above_: Barom.       - -    Inches 29, .5218:
  Attached Therm.       56°.6;    Air-ditto, 57°.
  Subtract the _colder_ —————   from the _warmer_,
and there remains 4° of Heat to be added to the _colder_ Barometer; to
give it an _equal_ Temperature: which is to be done by _the 1st Table_,
thus:

[Sidenote: Section, 356.]

To find the Expansion _with_ 4° of Heat, _on_ the _colder_ Barometer;
(which, as before, is the _upper_ Barometer) standing at Inches 29,
.5218 Tenths.

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