Now, what was that boy's weight, if a brick weighs equal to a three-quarter brick and three-quarters of a pound? 123.--A LEGAL DIFFICULTY. "A client of mine," said a lawyer, "was on the point of death when his wife was about to present him with a child. I drew up his will, in which he settled two-thirds of his estate upon his son (if it should happen to be a boy) and one-third on the mother. But if the child should be a girl, then two-thirds of the estate should go to the mother and one-third to the daughter. As a matter of fact, after his death twins were born--a boy and a girl. A very nice point then arose. How was the estate to be equitably divided among the three in the closest possible accordance with the spirit of the dead man's will?" 124.--A QUESTION OF DEFINITION. "My property is exactly a mile square," said one landowner to another. "Curiously enough, mine is a square mile," was the reply. "Then there is no difference?" Is this last statement correct? 125.--THE MINERS' HOLIDAY. Seven coal-miners took a holiday at the seaside during a big strike. Six of the party spent exactly half a sovereign each, but Bill Harris was more extravagant. Bill spent three shillings more than the average of the party. What was the actual amount of Bill's expenditure? 126.--SIMPLE MULTIPLICATION. If we number six cards 1, 2, 4, 5, 7, and 8, and arrange them on the table in this order:-- 1 4 2 8 5 7 We can demonstrate that in order to multiply by 3 all that is necessary is to remove the 1 to the other end of the row, and the thing is done. The answer is 428571. Can you find a number that, when multiplied by 3 and divided by 2, the answer will be the same as if we removed the first card (which in this case is to be a 3) From the beginning of the row to the end? 127.--SIMPLE DIVISION. Sometimes a very simple question in elementary arithmetic will cause a good deal of perplexity. For example, I want to divide the four numbers, 701, 1,059, 1,417, and 2,312, by the largest number possible that will leave the same remainder in every case. How am I to set to work Of course, by a laborious system of trial one can in time discover the answer, but there is quite a simple method of doing it if you can only find it. 128.--A PROBLEM IN SQUARES. We possess three square boards. The surface of the first contains five square feet more than the second, and the second contains five square feet more than the third. Can you give exact measurements for the sides of the boards? If you can solve this little puzzle, then try to find three squares in arithmetical progression, with a common difference of 7 and also of 13. 129.--THE BATTLE OF HASTINGS.