The second member of this equation shows the sum of all the external
forces acting on one portion of the beam, that portion being limited
by the section about which the moment _M_ acts. That sum of all the
external forces, as given by the second member of equation (16_b_),
is evidently the total transverse shear at the section considered.
Equation (16_b_) then shows, in the language of the differential
calculus, that the first derivative of _M_ in respect to _x_ is
equal to the total transverse shear. It is further established in
the differential calculus that whenever a function, such as _M_, the
bending moment, is a maximum or a minimum, the first derivative is
equal to zero. The application of this principle to equation (16_b_)
shows that the bending moment in any beam or truss has its greatest
value wherever the shear is zero. Hence, in order to determine at what
section the bending moment has its greatest value in any loaded beam
carrying a given system of loads, it is only necessary to sum up all
the forces or loads, including the reaction _R_, on that beam from one
end to the point where that sum or shear is zero; at this latter point
the greatest moment sought will be found. This is a very simple method
of determining the section at which the greatest moment in the beam
exists.
The preceding formulæ and diagrams may be extended to include any
number of loads, and they are constantly used in engineering practice,
not only for beams and girders in buildings, but also for bridges
carrying railroad trains. Whatever may be the number of loads,
the expressions for the bending moments at the various points of
application of those loads are to be written precisely as indicated in
equations (16). When the number of loads becomes great the number of
terms in the equations correspondingly increase, but in reality they
are just as simple as those for a smaller number of loads.
The diagram for the vertical shear in this beam is the lower part of
Fig. 13. As in the case of Fig. 12 the shear at _A_ is the reaction
_R_, as it is _Rʹ_ at the other end of the beam. The shear in the
portion _AD_ of the beam has the value _R_, but in passing the point
_D_ to the right the weight _W₁_ represented by _OT_ must be subtracted
from _R_, so that the shear over the section _b_ of the span is _R_ -
_W₁_ or _QV_ in the diagram. Similarly, in passing the point _H_ toward
the right, both _W₂_ and _W₁_ must be subtracted from _R_, giving the
negative shear (the previous shear being taken positive) _VW_. The
negative shear _VW_ remains constant throughout the distance _c_, but
is increased by _W₃_ at the point _L_, so that throughout the distance
_d_ the shear _Sʹ_ = _-Rʹ_. These shear values are all shown in the
lower portion of Fig. 13 by the vertical shaded lines. Obviously it is
a matter of indifference whether the shear above the straight line _GJ_
is made positive or negative; it is only necessary to recognize that
the signs are different.
Public-domain text, read in full here on John Shaqi.
Reviews
Reviews
No reviews yet
Be the first to share your thoughts on this work.
Elsewhere in the archive
Join the Discussion
Join the discussion
Sign in to leave a comment or review.
Sign InorCreate an account