The following description will, I hope, give an idea of the general
features of the mechanical method employed by Archimedes. Suppose that X
is the plane or solid figure the area or content of which is to be
found. The method in the simplest case is to weigh infinitesimal
elements of X against the corresponding elements of another figure, B
say, being such a figure that its area or content and the position of
its centre of gravity are already known. The diameter or axis of the
figure X being drawn, the infinitesimal elements taken are parallel
sections of X in general, but not always, at right angles to the axis or
diameter, so that the centres of gravity of all the sections lie at one
point or other of the axis or diameter and their weights can therefore
be taken as acting at the several points of the diameter or axis. In the
case of a plane figure the infinitesimal sections are spoken of as
parallel _straight lines_ and in the case of a solid figure as parallel
_planes_, and the aggregate of the infinite number of sections is said
to _make up_ the whole figure X. (Although the sections are so spoken of
as straight lines or planes, they are really indefinitely narrow plane
strips or indefinitely thin laminae respectively.) The diameter or axis
is produced in the direction away from the figure to be measured, and
the diameter or axis as produced is imagined to be the bar or lever of a
balance. The object is now to apply all the separate elements of X at
_one point_ on the lever, while the corresponding elements of the known
figure B operate at different points, namely, _where they actually are_
in the first instance. Archimedes contrives, therefore, to move the
elements of X away from their original position and to concentrate them
at one point on the lever, such that each of the elements balances,
about the point of suspension of the lever, the corresponding element of
B acting at its centre of gravity. The elements of X and B respectively
balance about the point of suspension in accordance with the property of
the lever that the weights are inversely proportional to the distances
from the fulcrum or point of suspension. Now the centre of gravity of B
as a whole is known, and it may then be supposed to act as one mass at
its centre of gravity. (Archimedes assumes as known that the sum of the
"moments," as we call them, of all the elements of the figure B, acting
severally at the points where they actually are, is equal to the moment
of the whole figure applied as one mass at one point, its centre of
gravity.) Moreover all the elements of X are concentrated at the one
fixed point on the bar or lever. If this fixed point is H, and G is the
centre of gravity of the figure B, while C is the point of suspension,
X : B = CG : CH.
Thus the area or content of X is found.
Public-domain text, read in full here on John Shaqi.
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