+------------------------------------+----------+-------------+-------------+ | | | Sun’s Anom. | Moon’s Ano. | | | D. H. M. +-------------+-------------+ | | | s ° ʹ | s ° ʹ | | +----------+-------------+-------------+ | Tab. I. Mean New Moon in _March_ | | | | | A. D. 1777 | 27 7 53 | 9 7 27 | 5 25 51 | | From which subtract 2200 years | | | | | in Tab. V. | 6 21 47 | 11 16 26 | 4 20 37 | | | -------- | ---------- | ---------- | | Mean Conj. and Anom. in _March_ | | | | | before Chr. 424 | 20 10 6 | 9 21 1 | 1 5 14 | | Which with, the total of the three | +-------------+ | | Equations added | 9 20 | Equ. Moon’s Anom. - 19 | | | -------- | ---------- | | Gives the true time of Conjunction | 20 19 26 | Anom. cor. 1 4 55 | | +----------+ Sun’s Equat. + 1 48 | | Which was the 21st day of _March_, at | --------- | | 26 minutes past 7 in the morning at | Moon’s Ano. 1 6 43 | | _London_: and if 1 hour 35 minutes +---+---------------------------+ | be added for _Athens_, which is 23° 52ʹ | Moon’s ann. Eq. 0^h 20^m add | | east of the meridian of _London_, we | Her ellipt. Equ. 5 43 add | | have the time at _Athens_; namely, | Sun’s Equation 3 17 add | | 1 minute past 9 in the morning. | Total 9 20 add | +-------------------------------------------+-------------------------------+ EXAMPLE II. _To find the time of Full Moon in_ October, _the year before Christ 4030_. The years 1771 added to 4029 make 5800, or 58 Centuries.