Astronomy Explained Upon Sir Isaac Newton's Principles: And made easy to those who have not studied mathematicsFerguson, James
Science
Astronomy Explained Upon Sir Isaac Newton's Principles: And made easy to those who have not studied mathematics
Ferguson, James
Astronomy -- Early works to 1800
+---------------------------------------------+-------------+-------------+
| | Sun’s Long. | Sun’s Anom. |
| +-------------+-------------+
| | s ° ʹ ʺ | s ° ʹ |
| From the Sun’s mean Longitude and Anomaly +-------------+-------------+
| at the beginning of the year Christ 1 | 9 7 53 10 | 6 29 54 |
| Subtract his mean Motion and Anomaly for | | |
| 600 years | 0 4 32 0 | 11 24 2 |
| + ----------- | ---------- |
| And the remainder, or radix, is | 9 3 21 10 | 7 5 52 |
| To which add what 585 wants of 600, | | |
| _viz._ 15 years | 11 29 22 27 | 11 29 7 |
| { _May_ | 3 28 16 40 | 3 28 17 |
| { days 28 Bissextile | 0 28 35 2 | 0 28 35 |
| And also those of { hours 4 | 0 9 51 | 0 10 |
| { min. 3 | 0 7 | ---------- |
| { sec. 42 | 2 | 0 2 1 |
| | ----------- | Sun’s Anom. |
| Sun’s mean Long. _May_ 28th, at 4 hour | +-------------+
| 3 min. 24 sec. afternoon | 1 29 45 19 | |
| Equation of the Sun’s mean Place subtract | 2 2 | 2ʹ 22ʺ |
| | ----------- | Sun’s Equat.|
| Rem. his true Place for the same time, | | subtract. |
| _viz._ ♉ Taurus 29° 43ʹ 17ʺ | 1 29 43 17 | |
+---------------------------------------------+-------------+-------------+
_N. B._ As the Longitudes or Places of all the visible Stars in the
Heavens are well known, we have an easy method of finding the Sun’s true
Place in the Ecliptic: for the Sun is directly opposite to that Point of
the Ecliptic which comes to the Meridian at mid-night.
_To find the Sun’s Declination._
[Sidenote: Fourth Element.]
362. PRECEPT. Enter Table XVII with the Signs and Degrees of the Sun’s
Place; and making proportions, take out his Declination answering
thereto. If the Signs are at the head of the Table, the Degrees are at
the left hand; but if the Signs are at the foot of the Table, the
Degrees are at the right hand. So, the Sun’s Declination answering to
his true Place (found by § 359 to be 0^s 12° 9ʹ) is 4 degrees 48 minutes
54 seconds, making allowance for the 9ʹ that his Place exceeds 12°.
_To find the Angle of the Moon’s visible Path with the Ecliptic._
[Sidenote: Fifth Element.]
Public-domain text, read in full here on John Shaqi.
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