PRECEPT. This we may state at 5 degrees 38 minutes, as near enough for the purpose; since it is never above 8 minutes of a degree more or less. _To find the Moon’s Latitude._ [Sidenote: Sixth Element.] 363. PRECEPT. Having found the Sun’s distance from the Ascending Node by § 357, at the mean time of New Moon, and his Anomaly for that time by § 359, find the Equation of the Node in Table XIII, by the Sun’s Anomaly, and the Equation of the Sun’s mean Place in Table XII by his Anomaly: these two Equations applied (as the titles direct) to the Sun’s mean distance from the Ascending Node, give his true distance from it, and also the Moon’s true distance at the time of Change: but when the Moon is Full, this distance must be increased by the addition of 6 Signs, which will then be the Moon’s true distance from the same Node. The Moon’s true distance from the Ascending Node is called the _Argument of the Moon’s Latitude_; with the Signs of which, at the head of Table XIV, and Degrees at the left hand, or with the Signs at the foot of the Table and Degrees at the right hand, take out the Moon’s Latitude: which is _North Ascending_, _North Descending_, _South Ascending_, or _South Descending_, according to the letters _NA_, _ND_, _SA_ or _SD_, annexed to the Signs of the said Argument. [Illustration: Plate XII. _The Geometrical Construction of Solar and Lunar Eclipses._ _J. Ferguson delin._ _J. Mynde Sculp._] EXAMPLE. s ° ʹ Sun’s mean Dist. from the [83]Node at New Moon in _April 1764_ 0 5 37 To which add the Equation of the Node + 10 ---------- And it gives the Sun’s corrected Distance from the Node 0 5 47 To which cor. Dist. add the Eq. of the Sun’s mean Place + 1 56 ---------- And it gives the Sun’s true Distance from the Node 0 7 43 Which, being at the time of New Moon, is the _Argument of Latitude_; and in Table XIV, (making proportions for the 43ʹ) shews the Moon’s Latitude to be 40ʹ 9ʺ _North Ascending_[84]. _To find the Moon’s true hourly Motion from the Sun._ [Sidenote: Seventh Element.] 364. PRECEPT. With the Moon’s Anomaly enter Table XV, and thereby take out her true hourly Motion: then with the Sun’s Anomaly take out his true hourly Motion from the same Table: which done, subtract the Sun’s hourly Motion from the Moon’s, and the remainder will be the Moon’s true hourly Motion from the Sun; which, for the above time § 359, is 27ʹ 50ʺ. _To find the Semi-diameters of the Sun and Moon as seen from the Earth at the above-mentioned time._ [Sidenote: Eighth and Ninth Elements.]