Bacon is Shake-Speare: Together with a Reprint of Bacon's Promus of Formularies and EleganciesDurning-Lawrence, Edwin, Sir
History
Bacon is Shake-Speare: Together with a Reprint of Bacon's Promus of Formularies and Elegancies
Durning-Lawrence, Edwin, Sir
Shakespeare, William, 1564-1616 -- Authorship -- Baconian theory
Bacon tells us that there are 24 letters in the alphabet (_i_ and _j_
being deemed to be forms of the same letter, as are also _u_ and _v_).
Bacon was himself accustomed frequently to use the letters of the
alphabet as numerals (the Greeks similarly used letters for numerals).
Thus A is 1, B is 2 ... Y is 23, Z is 24. Let us take as an example
Bacon's own name--B=2, a=1, c=3, O=14, n=i3; all these added together
make the number 33, a number about which it is possible to say a good
deal.[7] We now put the numerical value to each of the letters that
form the long word, and we shall find that their total amounts to the
number 287, thus:
H O N O R I F I C A B I L I T U
8 14 13 14 17 9 6 9 3 1 2 9 11 9 19 20
D I N I T A T I B U S
4 9 13 9 19 1 19 9 2 20 18 = 287
From a word containing so large a number of letters as twenty-seven it
is evident that we can construct very numerous words and phrases; but I
think it "surpasses the wit of man" to construct any "sentence" other
than the "revealed sentence," which by its construction shall reveal not
only the number of the page on which it appears--which is 136--but shall
also reveal the fact that the long word shall be the 151st word printed
in ordinary type counting from the first word.
On one side of the facsimile reproduction of part of page 136 of the
1623 folio, numbers are placed shewing that the long word is on the 27th
line, which was a skilfully purposed arrangement, because there are 27
letters in the word. There is also another set of numbers at the other
side of the facsimile page which shews that, counting from the first
word, the long word is the 151st word. How is it possible that the
revealing sentence, "Hi ludi F. Baconis nati tuiti orbi," can tell us
that the page is 136 and the position of the long word is the 151st
word? The answer is simple. The numerical value of the initial letters
and of the terminal letters of the revealed sentence, when added
together, give us 136, the number of the page, while the numerical value
of all the other letters amount to the number 151, which is the number
of words necessary to find the position of the long word
"Honorificabilitudinitatibus," which is the 151st word on page 136,
counting those printed in ordinary type, the italic words being of
course omitted.
The solution is as follows
HI
LUDI
F
BACONIS
NATI
TUITI
ORBI
the initial letters of which are
H L F B N T O
their numerical values being
8 11 6 2 13 19 14 = total 73
and the terminal letters are
I I S I I I
their numerical values being
9 9 18 9 9 9 = total 63
__
Adding this 63 to 73 we get 136
Public-domain text, read in full here on John Shaqi.
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