Electricity for the farm: Light, heat and power by inexpensive methods from the water wheel or farm engine — John Shaqi
Electricity for the farm: Light, heat and power by inexpensive methods from the water wheel or farm engineAnderson, Frederick Irving
Science
Electricity for the farm: Light, heat and power by inexpensive methods from the water wheel or farm engine
Anderson, Frederick Irving
Electricity in agriculture
Thus, let us say, our weir has an opening 30 inches wide, and the
water overflows through the opening at a uniform depth of 6-1/4
inches, when measured a few inches behind the board at a point before
the overflow curve begins. Run down the first column on the left to
"6", and cross over to the second column to the right, headed "1/4".
This gives the number of cubic feet per minute for this depth one inch
wide, as 6.298. Since the weir is 30 inches wide, multiply 6.298 × 30
= 188.94--or, say, 189 cubic feet per minute.
Once the weir is set, it is the work of but a moment to find out the
quantity of water a stream is delivering, simply by referring to the
above table.
_Another Method of Measuring a Stream_
Weirs are for use in small streams. For larger streams, where the
construction of a weir would be difficult, the U. S. Geological Survey
engineers recommend the following simple method:
Choose a place where the channel is straight for 100 or 200 feet, and
has a nearly constant depth and width; lay off on the bank a line 50
or 100 feet in length. Throw small chips into the stream, and measure
the time in seconds they take to travel the distance laid off on the
bank. This gives the surface velocity of the water. Multiply the
average of several such tests by 0.80, which will give very nearly the
mean velocity. Then it is necessary to find the cross-section of the
flowing water (its average depth multiplied by width), and this
number, in square feet, multiplied by the velocity in feet per second,
will give the number of cubic feet the stream is delivering each
second. Multiplied by 60 gives cubic feet a minute.
_Figuring a Stream's Horsepower_
By one of the above simple methods, the problem of _Quantity_ can
easily be determined. The next problem is to determine what _Head_ can
be obtained. _Head_ is the distance in feet the water may be made to
fall, from the Source of Supply, to the water wheel itself. The power
of water is directly proportional to _head_, just as it is directly
proportional to _quantity_. Thus the typical weir measured above was
30 inches wide and 6-1/4 deep, giving 189 cubic feet of water a
minute--_Quantity._ Since such a stream is of common occurrence on
thousands of farms, let us analyze briefly its possibilities for
power: One hundred and eighty-nine cubic feet of water weighs 189 ×
62.5 pounds = 11,812.5 pounds. Drop this weight one foot, and we have
11,812.5 foot-pounds. Drop it 3 feet and we have 11,812 × 3 =
35,437.5 foot-pounds. Since 33,000 foot-pounds exerted in one minute
is one horsepower, we have here a little more than one horsepower. For
simplicity let us call it a horsepower.
[Illustration: Detail of a water-power plant, showing setting of
wheel, and dynamo connection]
Public-domain text, read in full here on John Shaqi.
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