Fundamental Philosophy, Vol. 1 (of 2)Balmes, Jaime Luciano
Philosophy
Fundamental Philosophy, Vol. 1 (of 2)
Balmes, Jaime Luciano
Philosophy, Spanish
286. We will complete this explanation with an example from elementary
geometry. "The surface of a rhomboid is equal to the surface of a
rectangle having the same base and altitude." First: in the idea of the
rhomboid, we do not see the idea of its equality with the rectangle;
and this we cannot see, because the relation does not exist when there
is no other term to which it may relate. The idea of the parallelogram
does not contain that of the rectangle, and consequently not that of
equality. Second: the relation results from the comparison of the
rhomboid with the rectangle; and, consequently, it must be found in a
total conception containing them both. It cannot, therefore, be said
that we add any thing to the conception of the parallelogram which
does not belong to it. On the contrary, we see this equality flow from
the conception of the rhomboid and that of the rectangle, as partial
conceptions of the total conception, formed by the combination of them
both. The analysis of this total conception opens to us the relation we
are now in quest of; for it must be observed that when the simple union
of the conceptions compared does not suffice, we make use of another
including them, and also something more; and from the new conception,
duly analyzed, we deduce the relation of the parts compared.
287. In the geometrical construction, that serves for the
demonstration of the above theorem, which we have used as an example,
may be seen what we have just explained with regard to total
conceptions containing other conceptions besides those compared. If we
place the rectangle and the rhomboid upon the same base, we at once see
that there is something common to both, namely, the triangle formed by
the base, a part of one side of the rhomboid, and a part of one side of
the rectangle. Neither synthesis nor analysis is here required, because
there is perfect coincidence, and this in geometry is equivalent to
perfect equality. The difficulty is in the two remaining parts, that
is, in the trapezoids to which the parallelograms are reduced by the
subtraction of the common triangle. The mere sight of the figures
teaches nothing concerning the equivalence of the two surfaces; we see
only that the two sides of the rhomboidal surface go on extending,
but including a less distance in proportion as the angle becomes more
oblique, under these two conditions: length of sides, and diminution of
distances between two limits, of which one is infinity, and the other
the rectangle. The relation of the equivalence of the surfaces may be
demonstrated by prolonging the parallel opposite the base, and thus
forming a quadrilateral of which the trapezoids are parts; to discover
the equality of these trapezoids, it is only necessary to decompose
the quadrilateral, attending to the equality of two triangles, each
respectively formed by one of the trapezoids and a common triangle.
Is any thing here added to the conception of each trapezoid? No. We
only compare them.
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