Hawkins Electrical Guide v. 03 (of 10): Questions, Answers, & Illustrations, A progressive course of study for engineers, electricians, students and those desiring to acquire a working knowledge of electricity and its applicationsHawkins, N. (Nehemiah)
Science
Hawkins Electrical Guide v. 03 (of 10): Questions, Answers, & Illustrations, A progressive course of study for engineers, electricians, students and those desiring to acquire a working knowledge of electricity and its applications
Hawkins, N. (Nehemiah)
Electrical engineering -- Handbooks, manuals, etc.
[Illustration: Fig. 544.--Queen weight voltameter for determining the
strength of current by the weight of metal deposited in a given time.
The two outside plates form the anode and are joined together and to one
binding post, while the cathode is placed between them and connected to
the other binding post. The cathode thus receives a deposit on both sides.
An adjustable arm serves to lower the plates into the electrolyte. To
calculate the strength of an unknown current which has passed through a
weight voltameter, _divide the gain in weight by the number of seconds
the current flows through the instrument and by the weight deposited by
one ampere in one second_. That is, current strength in amperes = gain in
weight ÷ (time in seconds × .0003286).]
Ques. How much copper or zinc will one ampere deposit in one second?
Ans. .0003286 gramme of copper in a copper voltameter, or .0003386 gramme
of zinc in a zinc voltameter.
Ques. What is the difference between an ampere and a coulomb?
Ans. An ampere is the unit _rate of flow_ of the current, and a coulomb
is the unit _quantity_ of electricity, that is, the ampere is the rate of
current flow that will deposit .0003286 grammes of copper in one second
and a coulomb is the _quantity_ of electricity that passes a given point
in one second when the current strength is one ampere. In other words a
coulomb is one _ampere second_.
[Illustration: Fig. 545.--Gas voltameter for determining the strength of
current by the volume of gas evolved. To use, connect up as shown in the
illustration. Adjust so that the zero position of the burette is about
one-half inch below the level of the top of the U tube. Pour acidulated
water into the mouth of the burette till the water in the U tube is about
one-half inch from the top. With the electrodes inserted through the
corks, _carefully_ place each one in position by giving a slight twist to
the right as the cork enters. The water level in the U tube and burette
should now be the same, or further adjustment must be made to attain this
result. The level in the burette does not necessarily have to correspond
with the zero graduation, but must not be below it. Unclamp the burette
and hold it nearly horizontal. The liquid will not run out if the corks
be tight, so that this is the _air leakage test_. Attach the connectors
and wires from the current source (which should have a pressure of 2 or
more volts) placing a switch in the circuit. When the switch is closed,
bubbles of gas will rise in the U tube from both electrodes, displacing
the water and forcing it up the burette. Hydrogen will be liberated over
the negative electrode, and oxygen over the positive electrode in the
proportion of twice as much hydrogen as oxygen. To calculate the current
strength, _divide the volume of gas liberated by the time in seconds, and
by the volume of gas liberated (in cubic centimeters) by one ampere in one
second and by .1733_; that is: amperes = volume of gas liberated ÷ (time
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