James Clerk Maxwell and Modern PhysicsGlazebrook, Richard
History
James Clerk Maxwell and Modern Physics
Glazebrook, Richard
Maxwell, James Clerk, 1831-1879; Physics -- History
In the third part of his paper Maxwell considers the consequences
of supposing the particles not to be spherical. In this case the
impacts would tend to set up a motion of rotation in the particles.
The direction of the force acting on any particle at impact would not
necessarily pass through its centre; thus by impact the velocity of its
centre would be changed, and in addition the particles would be made to
spin. Some part, therefore, of the energy of the particles will appear
in the form of the translational energy of their centres, while the
rest will take the form of rotational energy of each particle about its
centre.
It follows from Maxwell’s work that for each particle the average value
of these two portions of energy would be equal. The total energy will
be half translational and half rotational.
This theorem, in a more general form which was afterwards given to
it, has led to much discussion, and will be again considered later.
For the present we will assume it to be true. Clausius had already
called attention to the fact that some of the energy must be rotational
unless the molecules be smooth spheres, and had given some reasons
for supposing that the ratio of the whole energy to the energy of
translation is in a steady state a constant. Maxwell shows that for
rigid bodies this constant is 2. Let us denote it for the present by
the symbol β. Thus, if the translational energy of a molecule is ½ _m_
_v_², its whole energy is ½ β _m_ _v_².
The temperature is still measured by the translational energy, or ½ _m_
_v_²; the heat depends on the whole energy. Hence if H represent the
amount of heat--measured as energy--contained by a single molecule,
and T its temperature, we have--
H = βT
From this it can be shewn[50] that if γ represent the ratio of the
specific heat of a gas at constant pressure to the specific heat at
constant volume, then--
β = ⅔ 1/(γ-1)
For air and some other gases the value of γ has been shown to be 1·408.
From this it follows that β = 1·634. Now, Maxwell’s theory required
that for smooth hard particles, approximately spherical in shape, β
should be 2, and hence he concludes “we have shown that a system of
such particles could not possibly satisfy the known relation between
the two specific heats of all gases.”
Since this statement was made many more experiments on the value of γ
have been undertaken; it is not equal to 1·408 for _all_ gases. Hence
the value of β is different for various gases.
It is of some importance to notice that the value of β just found for
air is very approximately 1·66 or 5/3.
For mercury vapour the value of γ has been shown by Kundt to be 1·33
or 1⅓, and hence β is equal to 1. Thus all the energy of a particle of
mercury vapour is translational, and its behaviour in this respect is
consistent with the assumption that a particle of mercury vapour is a
smooth sphere.
Public-domain text, read in full here on John Shaqi.
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