Manual for the Solution of Military CiphersHitt, Parker
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Manual for the Solution of Military Ciphers
Hitt, Parker
Ciphers; Cryptography
Any substitution cipher, enciphered by a single alphabet composed of
letters, figures or conventional signs, can be handled by the methods
of case 6. For example, the messages under case 4-a and 5-a are easily
solved by these methods. But note that the messages under case 4-b
and 5-b cannot so be solved because several alphabets are used. We
will see later that there are methods of segregating the different
alphabets in some cases where several are used and then each of the
alphabets is to be handled as below.
Case 6-a.
Message
QDBYP BXHYS OXPCP YSHCS EDRBS ZPTPB BSCSB PSHSZ AJHCD OSEXV HPODA
PBPSZ BSVXY XSHCD
This message was received from a source which makes us sure it is in
Spanish. The occurrence of B, H, P and S has tempted us to try the
first two words as in case 4 and 5 but without result. We now prepare
a frequency table, noting at the same time the preceding and following
letter. This latter proceeding takes little longer than the preparation
of an ordinary frequency table and gives most valuable information.
Frequency Table
Prefix Suffix
A 11 2 ZD JP
B 11111111 8 DPRPBSPZ YXSBSPPS
C 11111 5 PHSHH PSSDD
D 11111 5 QECOC BROA
E 11 2 SS DX
F
G
H 111111 6 XSSJVS YCSCPC
I
J 1 1 A H
L
M
N
O 111 3 SDP XSD
P 111111111 9 YXCZTBHAB BCYTBSOBS
Q 1 1 D
R 1 1 D B
S 111111111111 12 YYCBBCPHOPBX OHEZCBHZEZVH
T 1 1 P P
U
V 11 2 XS HX
X 11111 5 BOEVY HPVYS
Y 1111 4 BHPX PSSX
Z 111 3 SSS PAB
It is clear from an examination of this table that we have to deal
with a single alphabet but one in which the letters do not occur in
their regular order.
We may assume that P and S are probably A and E, both on account of
the frequency with which they occur and the variety of their prefixes
and suffixes. If this is so, then B and H, are probably consonants
and may represent R and N respectively. D and X are then vowels by
the same method of analysis. Noting that HC occurs three times and
taking H as N we conclude that C is probably T. Substitute these
values in the last three words of the message because the letters
assumed occur rather frequently there.
PBPSZBSVXYXSHCD
Public-domain text, read in full here on John Shaqi.
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