Marks' first lessons in geometry: In two parts. Objectively presented, and designed for the use of primary classes in grammar schools, academies, etc. — John Shaqi
Marks' first lessons in geometry: In two parts. Objectively presented, and designed for the use of primary classes in grammar schools, academies, etc.Marks, Bernhard
Science
Marks' first lessons in geometry: In two parts. Objectively presented, and designed for the use of primary classes in grammar schools, academies, etc.
Marks, Bernhard
Geometry -- Study and teaching
As the line _d f_ is equal to the line _a c_, upon what point will the
point _f_ fall?
Then, if the point _e_ falls upon the point _b_, and the point _f_
upon the point _c_, where will the line _e f_ fall?
Now, because the three sides of the triangle _d e f_ exactly fall upon
the three sides of the triangle _a b c_, we say _the two magnitudes
coincide throughout their whole extent_, and are therefore equal.
What three parts of the triangle _a b c_ did we suppose to be equal to
three corresponding parts of the triangle _d e f_ before we placed
one upon the other.
What line of the one do we _find_ equal to a line in the other?
What two angles of the one do we _find_ equal to two angles in the
other?
What do you think of the areas of the triangles?
[Illustration]
DEMONSTRATION.
We wish to prove, that,
_If two triangles have two sides, and the included angle of the one
equal to two sides and the included angle of the other, each to
each, the two triangles are equal in all respects._
Let the triangles _a b c_ and _d e f_ have the side _a b_ of the one
equal to the side _d e_ of the other; the side _a c_ of the one
equal to the side _d f_ of the other; and the included angle _b a c_
of the one equal to the included angle _e d f_ of the other, each to
each; then will the two triangles be equal in all their parts.
For, place the triangle _d e f_ upon the triangle _a b c_, so that the
line _d e_ shall fall upon the line _a b_, with the point _d_ upon
the point _a_.
Because the line _d e_ is equal to the line _a b_, the point _e_ will
fall upon the point _b_.
Because the angle _e d f_ is equal to the angle _b a c_, the line _d
f_ will fall upon the line _a c_.
Because the line _d f_ is equal to the line _a c_, the point _f_ will
fall upon the point _c_.
Then, because the point _e_ is on the point _b_, and the point _f_ on
the point _c_, the line _e f_ will coincide with the line _b c_, and
the two triangles will be found equal in all their parts;
That is, the angle _e_ is found to be equal to the angle _b_, the
angle _f_ to the angle _c_, the line _e f_ to the line _b c_, and
the area of the triangle _a b c_ to the area of the triangle _d e
f_.
[Illustration]
PROPOSITION XIV. THEOREM.
DEVELOPMENT LESSON.
In these two triangles we have tried to make the angle _b_ of the one
equal to the angle _e_ of the other; the angle _c_ of the one equal
to the angle _f_ of the other; and the included side _b c_ of the
one equal to the included side _e f_ of the other.
We now wish to find out if the remaining angle _a_ of the one is equal
to the remaining angle _d_ of the other, and if the two remaining
sides _a b_ and _a c_ of the one are equal to the two remaining
sides _d e_ and _d f_ of the other.
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