from which C = 0.1165, and this number, according to the
conditions of the formula, is to be subtracted from the
observed reading. The true reading in the case given is,
therefore,
29.298 inches or 744.2 millimeters.
The observed reading 747.1 “
-----
And the correction 2.9 “
Unless extremely accurate work be required the correction for
temperature is of very little importance in nitrogen determinations
in fertilizers. Each instrument sent out by the Weather Bureau is
accompanied by a special card of corrections therefor, but these are of
small importance in fertilizer work. In order then to get the correct
weight of the gas from its volume the reading of the thermometer and
barometer at the time of measurement must be carefully noted. However,
after the end of the combustion, the azotometer should be carried into
another room which has not been affected by the combustion and allowed
to stand until it has reached the room temperature.
Every true gas changes its volume under varying temperatures at the
same rate and this rate is the coefficient of gaseous expansion.
For one degree of temperature it amounts to 0.003665 of its volume.
Representing the coefficient of expansion by K the volume of the gas as
read by V, the volume desired at any temperature by V′, the temperature
at which the volume is read by _t_ and the desired temperature by _t′_,
the change in volume may be calculated by the following formula:
V′ = V[1 + K(_t′_ - _t_)].
_Example._—Let the volume of nitrogen obtained by combustion be
thirty-five cubic centimeters, and the temperature of observation 22°.
What would be the volume of the gas at 0°?
Making the proper substitutions in the formula the equation is reduced
to the form below:
V′ = 35[1 + 0.003665(0°-22°)]
or V′ = 35(1 - 0.08063) = 32.18.
Thirty-five cubic centimeters of nitrogen therefore measured at 22°
become 32.18 cubic centimeters when measured at 0°.
When gases are to be converted into weight after having been determined
by volume, their volume at 0° must first be determined; but this
volume must also be calculated to some definite barometric pressure.
By common consent this pressure has been taken as that exerted by a
column of mercury 760 millimeters in height. Since the volume of a gas
is inversely proportional to the pressure to which it is subjected, the
calculation is made according to that simple formula. Let the reading
of the barometer, at the time of taking the volume of gas, be H, and
any other pressure desired H′. Then we have the general formula:
HV
V : V′ = H′ : H; and V′ = ----.
H′
Public-domain text, read in full here on John Shaqi.
Reviews
Reviews
No reviews yet
Be the first to share your thoughts on this work.
Elsewhere in the archive
Join the Discussion
Join the discussion
Sign in to leave a comment or review.
Sign InorCreate an account