Pyrometry: A Practical Treatise on the Measurement of High TemperaturesDarling, Charles R. (Charles Robert)
Science
Pyrometry: A Practical Treatise on the Measurement of High Temperatures
Darling, Charles R. (Charles Robert)
Pyrometry
log_{10}J = K_{1} + K_{2}(1/T) (2)
where K_{1} = log _c_{1}_-5 log λ and K_{2} = _c_{2}_(log _e_/λ).
This simplified expression shows a linear relation between log J and
1/T; and hence if the temperatures corresponding to two intensities
be known, the results may be plotted on squared paper in the form of
a straight line connecting T and J, from which line intermediate or
extraneous readings of temperatures may be obtained for any given
intensity. Another useful form of Wien’s equation, referring to the
ratio of two intensities J_{1} and J_{2}, is as under:—
┌ ┐
J_{1} _c_{2} log _e_ │ 1 1 │
log ───── = ─────────────── │───── - ───── │ (3)
J_{2} λ │ T_{2} T_{1}│
└ ┘
where T_{2} and T_{1} are the absolute temperatures corresponding to
J_{2} and J_{1} The value of _c_{2}_ is 1450000, when λ is expressed in
millionths of a centimetre. Evidently, if the ratio J_{1}/J_{2} and the
value of _c_{2}_, λ, and T_{2} be known, T_{1} may be calculated. When
λ is not known, as in the case of a piece of red glass for which its
value has not been determined, two readings at known temperatures will
establish the value of (_c_{2}_ log _e_)/λ, and all other results may
then be calculated. Examples illustrating the application of the formula
will now be given.
_Example I._—A black body at an absolute temperature
T_{1} is found to give twice the intensity observed at
1200° abs., the comparison being made with red glass
transmitting wave-length 65 × 10^{-6} cms. To find the
value of T_{1}.
Applying values to formula (3)
┌ ┐
1450000 │ 1 1 │
log 2 = ─────── log 2·7183 × │ ──── - ──── │
65 │ 1200 T_{1 │
└ ┘
and ┌ ┐
1450000 × 0·4343 │ 1 T_{1} │
0·3010 = ──────────────── × │ ───── - ────── │
65 │ 1200 1 │
└ ┘
from which T_{1} = 1237° abs.
_Example II._—The intensity of the radiations from a black
body at 2000° abs. are found to be equal to those from a
given standard, taken as unity. To find the intensity at
3000 abs., compared with the same standard. λ = 65 × 10^{-6} cms.
Applying in (3) as before,
┌ ┐
J_{1} 1450000 × 0·43435 │ 1 1 │
log ──── = ───────────────── × │ ───── - ──── │
1 65 │ 2000 3000 │
└ ┘
Public-domain text, read in full here on John Shaqi.
Reviews
Reviews
No reviews yet
Be the first to share your thoughts on this work.
Elsewhere in the archive
Join the Discussion
Join the discussion
Sign in to leave a comment or review.
Sign InorCreate an account