Scientific American Supplement, No. 1082, September 26, 1896Various
Science
Scientific American Supplement, No. 1082, September 26, 1896
Various
Science -- Periodicals
After carrying these experiments to a successful conclusion, I found
that it was yet necessary to prove that, on reducing the vapor
pressure of boiling oxygen, to a minimum, no corresponding fall of
temperature takes place. The vessel, e, was partially filled with
liquid oxygen, and, by means of a small siphon, a small quantity of
the liquid was allowed to flow into the tube, a. The inner vessel, a,
was then connected with the air pump and manometer, and the pressure
was reduced to 2 mm. of mercury. The oxygen remained liquid and quite
clear. In a second experiment the temperature of the liquid oxygen,
boiling under 2 mm. of mercury pressure, was measured by means of a
thermometer. The temperature indicated lay above -220° C., a
temperature easily arrived at by means of liquid air. I, therefore,
concluded that liquid air was a much more efficient cooling agent than
liquid oxygen, and that it would be quite unnecessary to make further
experiments on the liquefaction of helium.
In every single instance I have obtained negative results, and, as far
as my experiments go, helium remains a permanent gas, and apparently
much more difficult to liquefy than even hydrogen. The small quantity
of the gas at my disposal, and, indeed, the extreme rarity of the
minerals from which it is obtained, compelled me to carry out my
investigation on a very small scale. Using a larger apparatus, and
working at a much higher pressure, I could have submitted the gas to
greater expansion. Further, I should have been able to measure the
temperature of the gas at the moment of expansion by means of a
platinum thermometer, as I did when working with hydrogen; but to make
such experiments I should have required 10, if not 100, liters of the
gas. As I was unable to determine the temperatures to which I cooled
the gas, by any experimental means, I have been obliged to calculate
them from Laplace's and Poisson's formula for the change of
temperature in a gas during adiabatic expansion.
T/T1 = (p/p1)^{(k - 1/k)}
Where:
T, p are the initial temperature and pressure of the gas.
T1, p1 are the final temperature and pressure of the gas.
k is the ratio (cp/cv) which, for a monatomic gas, is 1.66.
In the first series of experiments the gas, under a pressure of 128
atmospheres, was cooled down to -210° C.
p T p1 T1
At. Deg. At. Deg. Deg.
125 -210 C. 50 -229.3 C. 43.7 A.
... ... 20 -242.7 C. 30.3 A.
... ... 10 -250.1 C. 22.9 A.
... ... 5 -255.6 C. 17.4 A.
... ... 1 -263.9 C. 9.1 A.
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